Question Video: Finding the Area of a Square given Its Perimeter in Word Problems | Nagwa Question Video: Finding the Area of a Square given Its Perimeter in Word Problems | Nagwa

Question Video: Finding the Area of a Square given Its Perimeter in Word Problems Mathematics

A farmer has 53 1/3 feet of fencing and wants to build a square pen for his chickens? What is the area of the largest pen he can build?

03:16

Video Transcript

A farmer has 53 and one-third feet of fencing and wants to build a square pen for his chickens? What is the area of the largest pen he can build?

We’re told that the farmer wants to build a square pen using 53 and one-third feet of fencing. Since the fencing encloses the square, we can say that 53 and one-third feet is the perimeter of our square. Now, we also know that squares have four sides of equal length. Let’s call these 𝑥 feet.

So let’s begin by finding the value of 𝑥. To do this, we divide 53 and one-third by four. But we can’t really do that until we’ve converted our mixed number, 53 and one-third, into an improper or top heavy fraction. To do that, we multiply the integer part by the denominator of the fraction. That’s 53 times three, which is 159. We then add this value to the numerator of our fraction. 159 plus one is 160. This part forms the numerator of our top heavy or improper fraction. The denominator stays the same. It’s three.

And so the value of 𝑥 can be calculated by dividing 160 over three by four. Let’s write four as four ones or four over one and remind ourselves that to divide by a fraction we multiply by the reciprocal of that fraction. This process is sometimes called “keep, change, flip.”

We’re now going to cross-cancel by noticing that both 160 and four are divisible by four. When we divide 160 by four, we get 40. 40 times one is 40, and three times one is three. So we find that 𝑥 is equal to 40 over three or forty thirds.

Now, at this stage, we might be tempted to convert this back into a mixed number. But let’s check we’ve actually finished working with our fractions. We now know that the side length of our square is forty thirds feet. And the question asked us to find the area of the largest pen he can build. So we recall that the area of a square is found by squaring its side lengths. So the area of the pen is forty thirds squared.

Notice that had we converted this back into a mixed number, we wouldn’t be able to easily calculate this. But to square a single fraction, we square both the numerator and denominator. 40 squared is 1600, and three squared is nine. So the area is 1600 over nine square feet.

We’re now ready to convert this back into a mixed number. This time, we divide the numerator by the denominator. 1600 divided by nine is 177 with a remainder of seven. 177 forms the integer part of our mixed number, whereas the remainder forms the numerator of the fractional part. The denominator remains unchanged. This means that 1600 over nine is the same as 177 and seven-ninths. And since we’re working in feet, we can say that the area of the pen will be 177 and seven-ninths square feet.

Join Nagwa Classes

Attend live sessions on Nagwa Classes to boost your learning with guidance and advice from an expert teacher!

  • Interactive Sessions
  • Chat & Messaging
  • Realistic Exam Questions

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy