Video Transcript
In this video, weβll learn how to
use the theorems of intersecting chords, secants, or tangents and secants to find
missing lengths in a circle.
Letβs begin by recapping the names
of the various parts of a circle. By this stage, you should feel
confident in being able to identify a chord, a radius, or a diameter of a
circle. Then we know that a line that
intersects the circumference of a circle exactly once and is perpendicular to the
diameter of that circle is called the tangent. If the tangent has an endpoint on
the circumference of the circle, we then call it the tangent segment. And itβs important to realize that
the tangent segment extends in one direction infinitely.
Next, we have a secant line. Now thatβs a line that intersects a
curve at a minimum of two distinct points. The secant to a circle intersects
the circumference exactly twice, whilst a secant segment will intersect twice, but
an endpoint will lie on the circumference of that circle. So now we have these definitions;
weβre going to consider a couple of theorems that can help us to solve problems
involving circles.
The first is the intersecting
chords theorem. So we have a pair of chords π΄π΅
and πΆπ· that intersect at the point πΈ. The intersecting chords theorem
tells us that the products of the length of the line segments on each chord are
equal. So in this case, π΄πΈ times πΈπ΅ is
equal to the product of πΆπΈ and πΈπ·. If we define line segment π΄πΈ to
be π units, πΈπ΅ to be π units, and so one, we can alternatively write this as π
times π equals π times π. And then this is really useful
because we can rearrange this to represent these lengths proportionally such that π
over π is equal to π over π. And so the benefit of this theorem,
is that if we know any of these three values, we can find the fourth.
Now that we have the intersecting
chords theorem, weβre going to implement this in an example to help us find a
missing length.
If πΈπ΄ over πΈπ΅ is equal to
eight-sevenths, πΈπΆ is equal to seven centimeters, and πΈπ· is equal to eight
centimeters, find the length of line segments πΈπ΅ and πΈπ΄.
And we also have a diagram of a
circle which has two chords, π΄π΅ and πΆπ·. We notice that these chords
intersect at a point. Thatβs point πΈ. And this is really useful because
we can use the intersecting chords theorem to link the lengths of line segments
πΈπΆ, πΈπ΅, πΈπ΄, and πΈπ·. The intersecting chords theorem
tells us that the product of πΈπΆ and πΈπ· is equal to the product of the lengths of
line segments πΈπ΅ and πΈπ΄. In this case then, πΈπΆ times πΈπ·
is a πΈπ΅ times πΈπ΄.
The question tells us that πΈπΆ is
equal to seven centimeters whilst πΈπ· is equal to eight centimeters. Substituting these values into our
formula then, we get seven times eight is equal to πΈπ΅ times πΈπ΄ or 56 is equal to
πΈπ΅ times πΈπ΄. And at first glance, it might look
like we donβt have enough information to answer this question. But we havenβt used the
proportional relationship between πΈπ΄ and πΈπ΅. That is, πΈπ΄ over πΈπ΅ is equal to
eight-sevenths. By multiplying both sides of this
equation by πΈπ΅, we find that πΈπ΄ is equal to eight-sevenths πΈπ΅. And then we can replace πΈπ΄ with
this expression in our earlier equation.
This then becomes 56 is equal to
πΈπ΅ times eight-sevenths πΈπ΅ or 56 is eight-sevenths πΈπ΅ squared. Letβs solve this equation by
dividing by eight-sevenths. Now thatβs the same as dividing by
eight and then multiplying by seven, giving us 49 is equal to πΈπ΅ squared. The final step is to then find the
positive square root of 49. Now, usually we would find both the
positive and negative square root, but of course here this is giving us a
length. So weβre only interested in the
positive value. πΈπ΅ is therefore equal to seven or
seven centimeters.
Once we have this value, we can use
our earlier equation, that is, πΈπ΄ equals eight-sevenths πΈπ΅, to find the value of
πΈπ΄. πΈπ΄ is then eight-sevenths times
seven. Well, that, of course, is simply
equal to eight or eight centimeters. The length of line segment πΈπ΅ is
seven centimeters, and the length of line segment πΈπ΄ is eight centimeters.
So weβve demonstrated the
intersecting chords theorem. Weβre now going to introduce a
second theorem thatβs going to help us solve missing value problems with
circles. This theorem states that the
product of the measures of one secant segment and its external secant segment is
equal to the product of the measures of the other secant segment and its external
secant segment, where the two secant segments, of course, must intersect. In our diagram, that is π΄πΈ times
π΅πΈ equals πΆπΈ times π·πΈ.
Labeling the various segments as π
units, π units, and so on, we can alternatively write this as π times π equals π
times π. And this is useful to do because
the intersecting secants theorem has a special case. And we call it the tangent secant
theorem. If one or both of the lines are
tangent segments, then according to our diagram here we can say that π΄π΅ times π΅πΈ
is equal to the square of π·πΈ. So π times π is π squared. Weβll now demonstrate how to use
one of these theorems to solve a problem involving two secant lines that intersect
outside of the circle.
If πΈπΆ is equal to 10 centimeters,
πΈπ· is equal to six centimeters, πΈπ΅ equals five centimeters, find the length of
line segment πΈπ΄.
Then we have a diagram with a
circle with two intersecting secants drawn on it. Thatβs π΄πΈ and πΆπΈ. Since weβre dealing with a pair of
intersecting secant segments, weβll use the intersecting secants theorem. This is that the product of the
measures of one secant segment and its external secant segment is equal to the
product of the measures of the other secant segment and its external secant
segment. So in the case of our diagram,
thatβs πΈπ΄ times πΈπ΅ equals πΈπ· times πΈπΆ.
Now weβre told in the question the
length of line segment πΈπΆ to be 10 centimeters, πΈπ· is six centimeters, and πΈπ΅
is five centimeters. So letβs substitute these
dimensions into our equation. When we do, we find that πΈπ΄ times
five is equal to six times 10. Then we solve this equation for
πΈπ΄ by dividing both sides by five. So πΈπ΄ is six times 10 divided by
five. Now we could evaluate the numerator
of this fraction. Or alternatively, we spot that
there is a common factor between 10 and five. We can divide them both by
five. This means that πΈπ΄ is equal to
six times two divided by one. And thatβs 12 or 12
centimeters. The length of line segment πΈπ΄ is
then 12 centimeters.
In our next example, weβll
demonstrate how to use the special case of the intersecting secants theorem, that
is, the tangent secant theorem, where one of the lengths is, in fact, a tangent
segment.
In the figure shown, the circle has
a radius of 12 centimeters. π΄π΅ is equal to 12 centimeters,
and π΄πΆ is equal to 35 centimeters. Determine the distance from line
segment π΅πΆ to the center of the circle π and the length of line segment π΄π·,
rounding your answers to the nearest tenth.
Weβre going to begin by finding the
distance from line segment π΅πΆ to the center of the circle π. We might recall that the shortest
distance from a point to a line is the length of the perpendicular from that point
to the line. And so we construct this
perpendicular from point π to the line segment π΅πΆ. In fact, since π is the center of
the circle and π΅πΆ is a chord, we can say that this perpendicular is the
perpendicular line bisector of π΅πΆ. So defining the point where this
perpendicular meets the line segment π΅πΆ as πΈ, we can say that π΅πΈ must be equal
to πΈπΆ.
Next, weβre going to use the fact
that the radius of the circle is 12 centimeters. The radius, of course, is the line
segment that joins the point of the center of the circle to any point on its the
circumference. So we can say that ππ΅ is 12
centimeters.
Next, we apply the fact that π΄π΅
is equal to 12 centimeters and π΄πΆ is equal to 35 centimeters. Since we can think of line segment
π΄πΆ as the sum of line segments π΄π΅ and π΅πΆ, we can say that 35 is equal to 12
plus π΅πΆ and we can find the length of π΅πΆ by subtracting 12 from both sides of
this equation. 35 minus 12 is 23. So π΅πΆ is 23 centimeters in
length.
But remember, we said that the line
segment ππΈ is the perpendicular bisector for the line segment π΅πΆ. So π΅πΈ must be half of π΅πΆ, that
is, 23 divided by two or 23 over two centimeters. We now note that we have a right
triangle ππΈπ΅ for which we know two of its sides. We can therefore use the
Pythagorean theorem to find the length of the side ππΈ. Letβs call that π₯ or π₯
centimeters.
Substituting what we know about
this triangle into the Pythagorean theorem, and we find that 12 squared equals π₯
squared plus 23 over two squared. Then we make π₯ squared the subject
by subtracting 23 over two squared from both sides. 12 squared minus 23 over two
squared is 47 over four. To find the length that weβre
interested in, π₯, weβre going to find the positive square root of 47 over four. And thatβs equal to 3.427 and so
on. Correct the nearest tenth, we find
thatβs equal to 3.4 centimeters.
We now move on to the second part
of this question. And that asks us to find the length
of line segment π΄π·. And we observed that line segment
π΄π· is, in fact, a tangent segment, whilst the line π΄πΆ is a secant segment. This means we can use a special
version of the intersecting secants theorem. And thatβs called the tangent
secant theorem. In the case of our circle, it tells
us that the product of the lengths of line segments π΄π΅ and π΄πΆ is equal to the
square of the length of line segment π΄π·.
Now weβre given that π΄π΅ is 12
centimeters, whilst π΄πΆ is 35. So 12 times 35 is equal to π΄π·
squared, or π΄π· squared is equal to 420. Weβll solve this equation by
finding the square root of 420. That gives us that π΄π· is 20.493,
which correct the nearest tenth is 20.5 centimeters. The distance from line segment π΅πΆ
to the center of the circle π is 3.4 centimeters, and the length of line segment
π΄π· is 20.5 centimeters.
In our next example, weβll
demonstrate how to use these theorems to set up and solve equations to find missing
values.
In the following figure, find the
value of π₯.
And then we have a circle which
contains two chords. Those are chords π΄π΅ and πΆπ·. In fact, those chords intersect at
a point πΈ inside the circle. And so weβre going to link the
lengths of each of our respective line segments by using the intersecting chords
theorem. In the case of the given circle,
this tells us that the product of π΄πΈ and πΈπ΅ is equal to the product of πΆπΈ and
πΈπ·. Well, π΄πΈ times πΈπ΅, we see, is
π₯ plus eight times π₯ plus three, whilst πΆπΈ times πΈπ· can be written as π₯ times
π₯ plus 12.
Letβs distribute all of these
parentheses and then rearrange. The left-hand side of our equation
expands and simplifies to π₯ squared plus 11π₯ plus 24, whilst the right-hand side
simplifies to π₯ squared plus 12π₯. We then observe that we can
subtract π₯ squared from both sides of our equation. And weβre left with 11π₯ plus 24
equals 12π₯. Next, weβll subtract 11π₯ from both
sides. On the left-hand side weβre just
left with 24, whilst on the right we have 12π₯ minus 11π₯, which is simply π₯. And so, given the information about
our circle, we deduce π₯ to be equal to 24.
In our final example, weβll
demonstrate how to use the intersecting chords theorem in reverse.
Given that πΈπ΄ is 5.2 centimeters,
πΈπΆ equals six centimeters, πΈπ΅ equals 7.5 centimeters, and πΈπ· equals 6.5
centimeters, do the points π΄, π΅, πΆ, and π· lie on a circle?
And then weβre given a diagram. Now if these points lie on a
circle, then the line segments π΄π΅ and πΆπ· must themselves be chords to that
circle. And so if these points do indeed
lie on the circumference of the circle, then the respective line segments will
satisfy the intersecting chords theorem. This tells us that the product of
π΄πΈ and πΈπ΅ must be equal to the product of π·πΈ and πΈπΆ.
So letβs begin by working out the
product of π΄πΈ and πΈπ΅. π΄πΈ or πΈπ΄ is 5.2 centimeters,
whilst πΈπ΅ is 7.5 centimeters. And so their product is 5.2 times
7.5. And thatβs equal to 39. Then we want to find the product of
π·πΈ and πΈπΆ. Well, πΈπΆ is six centimeters, and
π·πΈ, which is equal to πΈπ·, is 6.5 centimeters. So their product is 6.5 times six,
which is also 39. And so we can say, yes, the points
π΄, π΅, πΆ, and π· must lie on the circumference of a circle. We might even give a reason and say
that since the line segments satisfy the intersecting chord theorem, π΄π΅ and πΆπ·
must be the chords of the same circle.
Weβll now recap the key points from
this lesson. In this lesson, we learned about
the intersecting chords theorem. And it says that the products of
the lengths of the line segments on each chord must be equal when those two chords
intersect. In other words, in this diagram,
π΄πΈ times πΈπ΅ equal πΆπΈ times πΈπ·. Similarly, the intersecting secants
theorem says that the product of the measures of one secant segment and its external
secant segment is equal to the product of the measures of the other secant segment
and its external secant segment. In the case of this diagram, π΄π΅
times π΅πΆ equals π΄π· times π΄πΈ. We also looked at a special case of
this called the tangent secant theorem, which applies where one or both of the lines
are tangent segments.