Question Video: The Relation between the Coefficient of a Quadratic Equation and Its Roots | Nagwa Question Video: The Relation between the Coefficient of a Quadratic Equation and Its Roots | Nagwa

Question Video: The Relation between the Coefficient of a Quadratic Equation and Its Roots Mathematics • First Year of Secondary School

If 𝐿 and 𝑚 are the roots of the equation 𝑥² + 20𝑥 + 15 = 0, what is the value of (1/𝑚) + (1/𝐿)?

02:19

Video Transcript

If 𝐿 and 𝑚 are the roots of the equation 𝑥 squared plus 20𝑥 plus 15 equals zero, what is the value of one over 𝑚 plus one over 𝐿?

We begin by reminding ourselves what the relationship between the coefficient of a quadratic equation is and its roots. For a quadratic equation whose leading coefficient is one, in other words, the coefficient of 𝑥 squared is one, the negative coefficient of 𝑥 tells us the sum of the roots and the constant term tells us the product. And this is really useful because the coefficient of 𝑥 here is 20 and the constant is 15. And so, the sum of our roots must be negative 20. Remember, we said that it’s the negative coefficient of 𝑥. Then, the product, which is the constant term, must be 15.

But of course, we were told that 𝐿 and 𝑚 are the roots of our equation. So we can, in fact, say that 𝐿 plus 𝑚 must be negative 20 and 𝐿 times 𝑚 must be 15. So, how does this help? We’re looking to find the value of one over 𝑚 plus one over 𝐿, and we can’t easily find two numbers that have a sum of negative 20 and a product of 15. So we’re going to need to manipulate our expressions. Let’s think of one over 𝑚 plus one over 𝐿.

We know that to add two fractions, we need to create a common denominator. Now, the easiest way to do this when working with algebraic fractions is to multiply both parts of each fraction by the denominator of the other. So, we’re going to multiply the numerator and denominator of our first fraction by 𝐿 and of our second fraction by 𝑚. That gives us 𝐿 over 𝐿𝑚 plus 𝑚 over 𝐿𝑚. And now since the denominators are the same, we simply add the numerators, and that gives us 𝐿 plus 𝑚 over 𝐿𝑚.

And this is really useful because we know that the numerator 𝐿 plus 𝑚 is equal to negative 20, and then the denominator 𝐿𝑚 is 15. And this means, in turn, that one over 𝑚 plus one over 𝐿 is equal to negative 20 over 15, which simplifies to negative four-thirds. And so, if 𝐿 and 𝑚 are the roots of our equation, then one over 𝑚 plus one over 𝐿 must be equal to negative four-thirds.

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