Video: Solving Word Problems Involving the Subtraction of Three-Digit Numbers

A student had 853 LE. He bought a bicycle for 587 LE. How much money is left?

02:18

Video Transcript

A student had 853 Egyptian pounds. He bought a bicycle for 587 Egyptian pounds. How much money is left?

There are two numbers in our question, 853 and 587. As the bicycle was bought for 587 Egyptian pounds and previously the student had 853 Egyptian pounds, we need to subtract 587 from 853. One way to do this is using column subtraction. When using this method, we need to ensure that we line up the hundreds, tens, and units underneath each other.

We begin by trying to subtract the numbers in the units column. However, we cannot subtract seven from three without getting a negative number. We can therefore go next door and borrow one from the tens column. The tens becomes a four. And we have 13 units. Subtracting seven units from 13 units gives us six in the units column.

Our next step is to try and subtract eight from four. Once again, we cannot do this. We can therefore borrow from the hundreds column, leaving us with seven in the hundreds column and 14 in the tens column. 14 minus eight is equal to six. And seven minus five is equal to two. Therefore, 853 minus 587 is equal to 266.

We can therefore say that the student has 266 Egyptian pounds left. We could check this answer by adding 266 to 587 and making sure our answer is 853. As this is correct, we know that the answer to the problem was that the student has 266 Egyptian pounds left.

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