Video Transcript
Find, without using a calculator,
one minus the cos of two π over one plus the cos of two π given tan of π equals
four, where π is an element of the interval π, three π over two.
Alright, so this is the fraction we
want to solve for. And to help us on our way, weβre
told that the tan of π equals four and that π, which is an angle, exists somewhere
in the third quadrant, from π to three π over two radians. Looking at the expression we want
to solve for, the first thing we can notice is that weβre taking the cos of two
times this angle π. This suggests that we can apply
whatβs called a double-angle identity.
And for the cosine function, there
are three different forms of this identity. With our aim being to simplify this
given fraction as much as possible, we can choose the particular forms of the
cosineβs double-angle identity that enable that. For example, in the numerator,
notice that we have one minus the cos of two π. If we were to replace the cos of
two π by one minus two times the sin squared of π, then notice that the positive
one and negative one in our numerator add up to zero. Similarly, if we replace the cos of
two π in our denominator with two times the cos squared of π minus one, then here
again we have a positive one and a negative one adding up to zero.
Accounting for all the sines
involved, this gives us two times the sin squared of π over two times the cos
squared of π. And we can see from here that the
twos will cancel from top and bottom. Noticing that we have a fraction of
a power of a sine over a power of a cosine, we can recall at this point that the tan
of an angle equals the sin of that angle over the cos of that angle. This implies that the tan squared
of π equals the sin squared of π over the cos squared of π. And therefore, our original
expression simplifies to the tan squared of π.
In our problem statement, weβre
told that the tan of π is four and also that this angle π exists in the third
quadrant. In this quadrant, the tangent
function is always positive. And this means we can safely
substitute in four for the tan of π and then square it to get a result of positive
16. This is the value of one minus the
cos of two π divided by one plus the cos of two π.