Question Video: Solving a Real-World Problem by Dividing Rational Numbers | Nagwa Question Video: Solving a Real-World Problem by Dividing Rational Numbers | Nagwa

Question Video: Solving a Real-World Problem by Dividing Rational Numbers Mathematics • First Year of Preparatory School

Each box of oranges weighs 8(3/8) kilograms. How many boxes are there if they weigh a total of 50.25 kilograms?

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Video Transcript

Each box of oranges weighs eight and three-eighths kilograms. How many boxes are there if they weigh a total of 50.25 kilograms?

In this question, we are told that the weight of a single box of oranges is eight and three-eighths kilograms. And we need to determine the number of boxes that would weigh 50.25 kilograms.

To answer this question, we can start by noting that two boxes will weigh two times the weight of a single box of oranges. Three boxes will weigh three times the weight of a single box. And, in general, 𝑛 boxes will weigh 𝑛 times the weight of a single box. Therefore, if we say that 𝑛 boxes weigh 50.25 kilograms, then we must have that eight and three-eighths times 𝑛 is equal to 50.25.

We want to solve this equation for 𝑛, so we want to isolate 𝑛 on the left-hand side of the equation. To do this, we will start by converting the weights into rational numbers. We do this by rewriting eight as 64 over eight, 50 as 200 over four, and 0.25 as one-quarter to obtain the equation 67 over eight times 𝑛 is equal to 201 over four.

To solve for 𝑛, we need to divide both sides of the equation by 67 over eight. This gives us that 𝑛 is equal to 201 over four divided by 67 over eight. To evaluate this division, we can recall that division by a fraction is the same as multiplying by its reciprocal. So, 𝑎 over 𝑏 divided by 𝑐 over 𝑑 is equal to 𝑎 over 𝑏 multiplied by 𝑑 over 𝑐. So, if we instead multiplied by the reciprocal of the weight of a box of oranges, we obtain 𝑛 equals 201 over four multiplied by eight over 67.

We can now evaluate this multiplication. We will do this by canceling the shared factor of 67 in the numerator and denominator to obtain a factor of three in the numerator and the shared factor of four in the numerator and denominator to find a factor of two in the numerator. This leaves us with three times two, which we can calculate is six.

It is worth noting that we can check our answer by checking that six boxes of oranges weigh 50.25 kilograms. To do this, we want to evaluate eight and three-eighths times six. We can evaluate this product by multiplying the integer and fractional part of the mixed number by six and adding the results. We have eight times six plus three over eight multiplied by six. In the second product, we can cancel the shared factor of two in the numerator and denominator to obtain three-quarters times three.

We can now evaluate each product. We have eight times six is 48 and three-quarters times three is nine-quarters. Finally, we can convert the fraction into a decimal and evaluate the sum to see that the weight of six boxes of oranges is 50.25 kilograms.

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