### Video Transcript

From point π΄ on a riverbank, a man looked at a house located on the other side of the river at point π΅ and found the direction to be 39 degrees north of east. He walked 147 meters east parallel to the river and arrived at point πΆ where point π΅ was 59 degrees north of east. Given the two riverbanks are parallel and points π΄, π΅, and πΆ are on the same horizontal level, find the width of the river giving the answer to the nearest meter.

Thereβs a lot of information given in the question, but helpfully weβve been given a diagram to represent it. We can see points π΄ and πΆ on one side of the river and point π΅, which represents the house, on the other side. The angles of 39 degrees and 59 degrees from each of the points π΄ and πΆ to the point π΅ are marked on the diagram. Each of these angles were described as north of east. So considering a compass where the northerly direction is taken to be the vertical direction on our screen, north of east would be an angle measured in this direction upwards from the easterly direction. Weβre also given the distance between points π΄ and πΆ, which is the 147 meters the man walked in an easterly direction parallel to the river.

Weβre asked to find the width of the river, which we can see marked on our diagram here. Now, we can see that it is a triangle formed by points π΄, π΅, and πΆ. But the width of the river isnβt one of the sides of this triangle. Instead, if we were to draw in a vertical line from point π΅ to the extension of line π΄πΆ, which meets this line at a right angle, then the width would be the length of the line segment π΅π·. We can label this as π€ meters, and it is a length in the right triangle π΅πΆπ·.

Currently, however, the only information we know about this triangle is that it is a right triangle with an angle of 59 degrees. We could work out the measure of the third angle in this triangle, but without the lengths of any sides, we wonβt be able to go any further.

Notice though that the side π΅πΆ is shared with triangle π΄π΅πΆ. And in triangle π΄π΅πΆ, we do know a side length. The length of π΄πΆ is 147 meters. So perhaps we can do some work in triangle π΄π΅πΆ first to enable us to work out the length of side π΅πΆ. In triangle π΄π΅πΆ then, we know that side π΄πΆ is 147 meters and angle π΅π΄πΆ is 39 degrees. We can also work out the measure of angle π΄πΆπ΅ because this angle is on a straight line with the angle of 59 degrees. Angles on a straight line sum to 180 degrees. So the measure of angle π΄πΆπ΅ is 180 degrees minus 59 degrees, which is 121 degrees.

We can also work out the measure of the third angle in triangle π΄π΅πΆ. Angles in a triangle sum to 180 degrees. So the measure of angle π΄π΅πΆ is 180 degrees minus 39 degrees minus 121 degrees, which is 20 degrees. In triangle π΄π΅πΆ, we now know the measures of all three angles and the length of one side. We want to calculate the length of a second side, side π΅πΆ, and we can do this using the law of sines.

This states that in any triangle π΄π΅πΆ where capital π΄, capital π΅, and capital πΆ represent the measures of the three angles and lowercase π, lowercase π, and lowercase π represent the lengths of the side opposite the angle with the corresponding letter, π over sin π΄ is equal to π over sin π΅, which is equal to π over sin πΆ. The side of length 147 meters is opposite the angle of 20 degrees, and the side whose length we wish to calculate, π΅πΆ, is opposite the angle of 39 degrees.

So using the law of sines, we can form an equation. π΅πΆ over sin of 39 degrees is equal to 147 over sin of 20 degrees. We can solve this equation to determine the length of π΅πΆ by multiplying both sides by sin of 39 degrees. That gives π΅πΆ equals 147 sin 39 degrees over sin of 20 degrees. We can now evaluate this on our calculator, which must be in degree mode, and it gives 270.481 continuing. Now, weβll keep that exact value on our calculator display.

Weβve now worked out the length of the side π΅πΆ, which, remember, was shared with triangle π΅πΆπ·. If we return to triangle π΅πΆπ·, which is a right triangle, we now know the length of one side and the measures of all the angles. We can therefore apply right triangle trigonometry to calculate the length of the side π΅π·, which will give the width of the river.

Labelling the three sides of this triangle in relation to the angle of 59 degrees, π΅π· is the opposite, πΆπ· is the adjacent, and π΅πΆ is the hypotenuse. The side whose length we know is the hypotenuse, and the side whose length we wish to calculate is the opposite. So recalling the acronym SOH CAH TOA, it is the sine ratio that we need to use to answer this question.

For an angle π in a right triangle, the sin of angle π is defined to be equal to the length of the opposite side divided by the length of the hypotenuse. So substituting 59 degrees for π, π€ for the opposite, and 270.481 continuing for the hypotenuse, we have sin of 59 degrees is equal to π€ over 270.481 continuing. To solve for π€, we multiply both sides by the denominator of 270.481 continuing. Now, if youβve kept that exact value on your calculator, you can now just type multiplied by sin of 59 degrees to give an exact value for π€. And it is 231.84 continuing.

Now, the question specifies that we should give our answer to the nearest meter. So weβre rounding to the nearest integer, and as the value in the first decimal place is an eight, weβre going to be rounding up.

So by first using the law of sines in a nonright triangle and then the sine ratio in a right triangle, we found the width of the river to the nearest meter is 232 meters.