### Video Transcript

A line πΏ passes through points three, three and negative one, zero. Work out the
equation of the line, giving your answer in the form ππ¦ plus ππ₯ plus π equals zero.

What weβre going to do first, is work out the equation of the line. And after that, weβll
focus on moving it into the form ππ¦ plus ππ₯ plus π.

To solve this problem, weβll need a few things. Letβs start with finding the slope and the
π¦-intercept. The formula for finding slope is, the changes in π¦ over the changes in π₯. And we
write that, π¦ two minus π¦ one over π₯ two minus π₯ one. We plug in these two points for our
formula for finding slope. π¦ two is zero, minus π¦ one, which is three. π₯ two is
negative one, minus π₯ one, which is three. We end up with negative three over negative four.
We can simplify our slope to π equals three-fourths.

Now that we know our π is three-fourths, we can use this slope intercept form to find the
intercept of this equation, to find our π. So we take our point negative one, zero and we
plug those values in for π₯ and π¦. This gives us zero equals three-fourths times negative one
plus π. When I multiply negative one by three-fourths, I get negative three-fourths. To get
π by itself, I add three-fourths to the right side of the equation. And if I add three-fourths
to the right side of the equation, I need to add three-fourths to the left side of the equation.
This means that our π¦-intercept equals three-fourths, π equals three-fourths.

So we use this formula, and we plug in the π and π that we found. This gives us π¦ equals
three-fourths π₯ plus three-fourths. Now we need to convert the slope intercept form into
ππ¦ plus ππ₯ plus π equals zero. This means that weβll move everything to the left side of the
equation, leaving only zero on the right side of the equation. We start that by subtracting
three-fourths π₯ from both sides of the equation. This leaves us with π¦ minus three-fourths π₯
equals three-fourths. Then I can subtract three-fourths from both sides of the equation, which
leaves me with π¦ minus three-fourths π₯ minus three-fourths equals zero.

But this is not our final answer. Because when we work with a form like this, we want π, π,
and π to be integers, which means we donβt wanna have fractions like three-fourths as π or π.
To fix this problem, we can multiply our entire form by four. We distribute the four to each
term in the equation. Four times π¦ equals four π¦. Four times negative three-fourths equals
negative three. Four times negative three-fourths equals negative three. Four times zero equals
zero.

This is the equation of line πΏ written as ππ¦ plus ππ₯ plus π. We would write four π¦ minus
three π₯ minus three equals zero.