Question Video: Solving Word Problems by Finding the Boundaries of an Absolute Value Inequality | Nagwa Question Video: Solving Word Problems by Finding the Boundaries of an Absolute Value Inequality | Nagwa

Question Video: Solving Word Problems by Finding the Boundaries of an Absolute Value Inequality Mathematics • Second Year of Secondary School

A factory produces cans with weight 𝑥 grams. To control the production quality, the cans are only allowed to be sold if |𝑥 − 183| ≤ 6. Determine the heaviest and the lightest weight of a can that can be sold.

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Video Transcript

A factory produces cans with weight 𝑥 grams. To control the production quality, the cans are only allowed to be sold if the absolute value of 𝑥 minus 183 is less than or equal to six. Determine the heaviest and the lightest weight of a can that can be sold.

The company uses this inequality to control the range of the weight that their cans can be. To find out the heaviest and the lightest weights, we need to see either end of this range. And that means we’ll need to solve for 𝑥.

When we’re dealing with absolute value, we need to break this up into two separate inequalities. First, we’ll have the case when 𝑥 minus 183 is less than or equal to six. After that, we consider the negative case, if the negative of 𝑥 minus 183 is less than or equal to six.

However, we’d rather multiply through by negative one. The negative of negative is a positive. We flip the sign, and then we have negative six, which makes our second inequality 𝑥 minus 183 is greater than or equal to negative six. To solve for 𝑥, we add 183 to both sides of our inequality. And we get 𝑥 is less than or equal to 189. When we add 183 to both sides of our other inequality, we see that 𝑥 is greater than or equal to 177.

The upper limit of the weight is going to be 189, while the lower end of the weight limit will be 177, which means the heaviest can that can be sold is 189 grams and the lightest can is 177 grams.

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