### Video Transcript

In the figure, which point can be used as the center of a circle that passes through
the two points π΄ and π΅?

Letβs recall that a circle can be mathematically defined as a set of points in a
plane that are a constant distance from a point in the center. For example, if we had these two points πΆ and π·, then with a point π which is
equidistant from both points πΆ and π·, we could create a circle with center π
which passes through both points πΆ and π·. Notice that the line segments πΆπ and π·π would both be radii of the circle.

In this problem, we need to consider which of the given points would be the center of
a circle which passes through π΄ and π΅. To do this, weβll need to consider which point is equidistant from π΄ and π΅. That means itβs the same distance away from both these points. If this was a question on paper, for example, we could get a ruler and measure the
distance of points π, π, and π from the points π΄ and π΅. The one which is equidistant from both points π΄ and π΅ would be the center of the
circle. But letβs consider this a little more mathematically.

We can consider this line πΏ sub two. πΏ sub two forms a 90-degree angle with the line segment π΄π΅. We can see from the marking on the line segment π΄π΅ that the line πΏ sub two divides
line segment π΄π΅ into two congruent pieces. We can therefore say that line πΏ sub two is the perpendicular bisector of line
segment π΄π΅. The really useful thing about the perpendicular bisector is it also gives us all the
points which are equidistant from two different points. And so, any point on the line πΏ sub two would be a point which is equidistant from
π΄ and π΅. That means that we could pick any point on this line πΏ sub two and draw a circle
which goes through π΄ and π΅. We also notice that of course the point π lies on this line. We could even draw a part of the circle which has center π and passes through π΄ and
π΅.

And so, the answer is that point π can be used as the center of the circle passing
through π΄ and π΅. Any other point on this line would also work. We can observe that point π would not work because the two line segments of π΄π and
π΅π are not congruent. In the same way, point π could not be the center of a circle because the line
segments π΄π and ππ΅ are different, leaving us with the answer of point π.