Question Video: Identifying a Carboxylic Acid From Its Reduced Product | Nagwa Question Video: Identifying a Carboxylic Acid From Its Reduced Product | Nagwa

Question Video: Identifying a Carboxylic Acid From Its Reduced Product Chemistry • Third Year of Secondary School

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The reduction of a carboxylic acid with hydrogen and a CuCr₂O₄ catalyst gives the following product. What structure did the original carboxylic acid have?

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Video Transcript

The reduction of a carboxylic acid with hydrogen and a CuCr2O4 catalyst gives the following product. What structure did the original carboxylic acid have?

In order to answer this question, we need to recognize what occurs during the reduction of a carboxylic acid. A carboxylic acid contains the carboxyl functional group. When a carboxylic acid is reacted with a reducing agent represented here by a capital H in brackets, the carboxyl functional group is reduced to a primary alcohol, and water is produced. This is the general equation for the reduction of a carboxylic acid. In this question, the reducing agent is hydrogen, typically in the form of hydrogen gas. And copper chromate is added as a catalyst. We are given the structure of the alcohol produced. Using this information, we need to determine the structure of the original carboxylic acid.

Let’s take another look at the general equation for guidance. Notice that the R group of the carboxylic acid remains unchanged when forming the alcohol, as does the carbon atom bonded to the R group. In addition, both molecules have a hydroxy group bonded in the same position. Thus, this portion of the carboxylic acid and alcohol, shown here in pink, are the same in both molecules. The difference between the two structures is that the double-bonded oxygen atom of the carboxylic acid is replaced by two hydrogen atoms to form the alcohol. This is not exactly what occurs during the reaction but can help us see how the two molecules are related to one another.

Now let’s look at the alcohol given in the question. We know that the alcohol and the original carboxylic acid will both have a hydroxy group bonded to a carbon atom which is bonded to the same R group. We saw in the general equation that the double-bonded oxygen atom of the carboxylic acid was replaced by two hydrogen atoms when forming the alcohol. Working backwards, we can see that the two hydrogen atoms in the alcohol must have originally been a double-bonded oxygen atom in the carboxylic acid. This structure for the molecule 3-methylbutanoic acid is the structure of the original carboxylic acid used in this reduction reaction.

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