Question Video: Determining the Second Major Resonance Structure of Nitric Acid | Nagwa Question Video: Determining the Second Major Resonance Structure of Nitric Acid | Nagwa

Question Video: Determining the Second Major Resonance Structure of Nitric Acid Chemistry • Second Year of Secondary School

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Nitric acid can exist as two major resonance structures. One of these structures is shown here. Which of the following structures is the other major resonance structure adopted by nitric acid? [A] Graph A [B] Graph B [C] Graph C [D] Graph D [E] Graph E

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Video Transcript

Nitric acid can exist as two major resonance structures. One of these structures is shown here. Which of the following structures is the other major resonance structure adopted by nitric acid?

In the five answer choices, we see five possibilities for the way that electrons can be distributed in the second resonance structure of nitric acid. Resonance structures are a set of two or more Lewis structures that demonstrate the delocalization of electrons in a chemical species. Resonance structures have the same connectivity of atoms, the same number of electrons, and the same chemical formula.

The chemical formula of nitric acid is HNO3. When looking at the structures in the answer choices, we can see that they all have the chemical formula HNO3 and that the atoms are connected in the same way. It’s difficult to tell if the structures have the same number of electrons because the lone pairs of electrons are not shown.

In the initial structure, we notice that there is a double bond between the nitrogen atom and an oxygen atom that has no other covalent bonds. In addition, there is a single bond between the nitrogen atom and another oxygen atom that also has no other covalent bonds. It’s important to remember that oxygen tends to have no more than two covalent bonds in a molecule, and a hydrogen atom will only have one single bond.

Resonance structures are often possible for a chemical species, in which a double bond is located next to a single bond. The oxygen atom involved in the double bond has two lone pairs of electrons. To have an octet of electrons, the oxygen atom on the left must have three lone pairs. We won’t discuss how to calculate formal charge in this video. However, it’s important to note that the leftmost oxygen atom has a formal charge of negative one and the nitrogen atom has a formal charge of positive one.

Now, resonance structures differ by the locations of lone pairs and bonding pairs. To draw a second resonance structure for nitric acid, we can convert a lone pair on the leftmost oxygen atom to a bonding pair, and also convert a bonding pair from the double bond into a lone pair on the top oxygen atom. So, the second resonance structure looks as if the double bond changed locations.

In reality, the electron pairs that we moved are delocalized, which means the electron density is spread out over the two oxygen atoms we’ve been discussing. However, in the resonance structure, the leftmost oxygen atom has two lone pairs and is shown as having a double bond, and the top oxygen atom has three lone pairs, a single bond, and is assigned a formal charge of negative one. The number of bonds around the nitrogen atom remained the same, so its formal charge did not change.

When looking at the answer choices, we can see that (A) cannot be the correct answer because the structure does not have a double bond. Structures (B) and (D) are also unlikely because one of the oxygen atoms has more than two bonds. In addition, a hydrogen atom cannot have more than one single covalent bond. Structure (E) is also incorrect because it contains two double bonds. This leaves answer choice (C), which matches the structure we drew.

In conclusion, the structure that is the second major resonance structure adopted by nitric acid is the one shown in answer choice (C).

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