Question Video: Solving One-Variable Equations Involving Negative Numbers | Nagwa Question Video: Solving One-Variable Equations Involving Negative Numbers | Nagwa

# Question Video: Solving One-Variable Equations Involving Negative Numbers Mathematics • Sixth Year of Primary School

## Join Nagwa Classes

Attend live Mathematics sessions on Nagwa Classes to learn more about this topic from an expert teacher!

If β6π₯ = 24, what is the value of 6π₯ β 1?

01:34

### Video Transcript

If negative six π₯ equals 24, what is the value of six π₯ minus one?

The steps here will be to first find what π₯ is equal to, then use that value to plug into the expression six π₯ minus one. Negative six π₯ equals 24 is the statement weβre given. We need to solve for π₯, get π₯ by itself. We can do that by dividing negative six π₯ by negative six.

Negative six divided by negative six cancels each other are out. Theyβre equal to one. But if we divide by negative six on the left side of the equation, we need to divide by negative six on the right side. 24 divide by negative six equals negative four. That tells us that π₯ is equal to negative four.

And we can use that information to solve six π₯ minus one. π₯ is equal to negative four. So we plug that in. Six times negative four minus one is what weβre trying to solve. Six π₯ negative four equals negative 24. If we subtract one from negative 24, we get negative 25. The value of six π₯ minus one is negative 25.

## Join Nagwa Classes

Attend live sessions on Nagwa Classes to boost your learning with guidance and advice from an expert teacher!

• Interactive Sessions
• Chat & Messaging
• Realistic Exam Questions

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy