Question Video: Finding the Equation of a Polynomial | Nagwa Question Video: Finding the Equation of a Polynomial | Nagwa

Question Video: Finding the Equation of a Polynomial Mathematics

Which of the following functions is graphed in the given figure? [A] 𝑦 = −(𝑥 − 5)³(𝑥 + 5) [B] 𝑦 = (𝑥 + 5)³(𝑥 − 5) [C] 𝑦 = −(𝑥 + 5)³(𝑥 − 5) [D] 𝑦 = (𝑥 − 5)³(𝑥 + 5) [E] 𝑦 = (𝑥 + 5)³(𝑥 − 5)²

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Video Transcript

Which of the following functions is graphed in the given figure? Option (A), (B), (C), (D), or (E).

We’re given a graph, and we need to determine which of five options is this a graph of. And we can see that all five of our options are polynomial functions. So we can use what we know about graphing polynomials to help us answer this question.

The first thing we can notice about our curve is its 𝑦-intercept is positive. It’s above the 𝑥-axis. And if we say that this is a curve 𝑦 is equal to some function 𝑓 of 𝑥, then the 𝑦-intercept happens when 𝑥 is equal to zero. In other words, we know that 𝑓 evaluated at zero is positive. So we could substitute 𝑥 is equal to zero into all five of our expressions to see which ones give us positive outputs.

For now though, let’s just keep in mind our 𝑦-intercept is positive. Instead, we’ll notice that there are two 𝑥-intercepts: one at negative five and one at 𝑥 is equal to five. And remember, at 𝑥-intercepts, our function is outputting zero. And by using the remainder theorem, if our polynomial is outputting zero when 𝑥 is equal to five, it must have a factor of 𝑥 minus five. In fact, it could have multiple. And the exact same will be true at negative five. Our function must have some factors of 𝑥 plus five. And these are the only 𝑥-intercepts. There’s no more linear factors.

However, it is worth pointing out there could’ve been some extra polynomial expression with no roots. And this on its own doesn’t help us answer this question because we can see all five of our options are in this form. However, we can combine this with what we know about the multiplicity of our function near its roots.

Let’s start by looking at the shape of our function near 𝑥 is equal to five. If we look closely, we can see this is very similar to a straight line. We could say that this shape is of the form 𝑦 is equal to negative 𝐴 times 𝑥 minus five to the first power or just 𝑥 minus five. The important thing to notice here is, though, that this is a straight line. And the shape of the graph for these roots must match the multiplicity of our function. In other words, because we have a straight line when 𝑥 is equal to five, the multiplicity of 𝑥 minus five must be one.

So let’s take a look at our five options. We can remove all of the options where the multiplicity of 𝑥 minus five is one. In option (A), the multiplicity of 𝑥 minus five is three. So option (A) can’t be the correct answer. Both options (B) and (C) have a multiplicity of one for 𝑥 minus five. So these could be correct. However, in option (D), its multiplicity is three. And in option (E), its multiplicity is two. So neither of these can be correct.

Now we’re ready to use our information about the 𝑦-intercept being positive. We’ll just substitute 𝑥 is equal to zero into both option (B) and option (C). Substituting 𝑥 is equal to zero into option (B), we get zero plus five all cubed times zero minus five. And if we were to evaluate this, we would get negative five to the fourth power or negative 625. And this is a negative answer, so it should appear below the 𝑥-axis on our diagram. Therefore, option (B) can’t be the correct option.

And for due diligence, let’s check option (C) in its entirety. We can substitute 𝑥 is equal to zero into the function in option (C) to find its 𝑦-intercept. If we do this, we get negative one multiplied by zero minus five all cubed times zero plus five. And if we evaluate this, we get five to the fourth power or 625.

And therefore, of the options listed, this can only be a sketch of the graph of the curve 𝑦 is equal to negative one times 𝑥 plus five all cubed times 𝑥 minus five.

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