Video Transcript
Fill in the blank: In the parallelogram π΄π΅πΆπ·, the vector ππ plus the vector ππ is equal to what.
Weβre looking at some geometric properties of vectors. So in order to understand whatβs going on here, letβs begin by sketching a parallelogram π΄π΅πΆπ·. Here is our parallelogram. Weβre ready to label the vertices. Letβs define this vertex, the bottom-left corner, to be vertex π΄. Then, since the parallelogram is said to be π΄π΅πΆπ·, one of the vertices adjacent to π΄ must be vertex π΅. Letβs choose this one. Then, the remaining vertex adjacent to π΅ is vertex πΆ, meaning the final vertex is vertex π·. Itβs worth noting of course that we could have moved in the opposite direction. Itβs just important that we follow the order the letters are given: π΄, π΅, πΆ, then π·.
Letβs now identify the relevant vectors. The first vector is vector ππ. This is the vector that describes the movement that takes us from point π΄ to point π΅ along a straight line. And so we can denote this using the yellow arrow. This is vector ππ. Next, weβre interested in the vector ππ. This is the vector that takes us directly from point π΄ to point π· along the straight line. So we denote this vector using the pink arrow as shown. Then, if weβre finding the sum of two vectors, we call that their resultant. And if we think about each vector as being like a journey, the resultant is essentially the final journey that we end up taking.
So, in this case, we move from point π΄ to point π΅ and then from point π΄ to point π·. But in terms of journeys, this doesnβt make a lot of sense. So we can use some of the properties of parallelograms to help us understand whatβs happening. We know that opposite sides in a parallelogram are both equal in length and parallel. And of course we know that vectors are defined by their magnitude and direction, not their position. This means that if we can describe the journey from π΄ to π· using the vector ππ, then we can describe the journey from π΅ to πΆ using that same vector.
And so now we can think about our resultant as taking us from point π΄ to point π΅ and then point π΅ to point πΆ. So the full journey found by adding ππ to ππ actually takes us from point π΄ to point πΆ. We can therefore describe the resultant of ππ and ππ using a single vector ππ. So, in the parallelogram π΄π΅πΆπ·, ππ plus ππ is equal to the vector ππ.