Question Video: Deriving Radical Functions | Nagwa Question Video: Deriving Radical Functions | Nagwa

Question Video: Deriving Radical Functions Mathematics

Given that 𝑥 = 𝑦⁵ + √(𝑦) + ∛(𝑦²), find d𝑦/d𝑥.

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Video Transcript

Given that 𝑥 is equal to 𝑦 to the power of five plus the square root of 𝑦 plus the cube root of 𝑦 squared, find d𝑦 by d𝑥.

We can find d𝑦 by d𝑥 by using the formula for the derivative of the inverse function. Which is that d𝑦 by d𝑥 is equal to one over d𝑥 by d𝑦. So we start by differentiating 𝑥 with respect to 𝑦. Let’s start by rewriting some of the terms in 𝑥. We can rewrite the square root of 𝑦 as 𝑦 to the power of a half and the cube root of 𝑦 squared as 𝑦 to the power of two over three. Now, we can use the power rule for differentiation in order to differentiate 𝑥 with respect to 𝑦, term by term.

We multiply by the power and decrease the power by one. This gives us that d𝑥 by d𝑦 is equal to five 𝑦 to the power of four plus one-half 𝑦 to the power of negative one-half plus two-thirds 𝑦 to the power of negative one-third. We can rewrite that fractional powers of 𝑦 back in their surd form. And then, we can combine these three terms into one fraction by creating a common denominator of six 𝑦. Our first term becomes 30𝑦 to the power of five over six 𝑦. Our second term becomes three multiplied by the square root of 𝑦 over six 𝑦. And our third term becomes four multiplied by the cube root of 𝑦 squared over six 𝑦. We obtain that d𝑥 by d𝑦 is equal to 30 multiplied by 𝑦 to the power of five plus three multiplied by the square root of five plus four multiplied by the cube root of 𝑦 squared all over six 𝑦.

Now, we can apply the formula for the derivative of the inverse function. And this gives us our solution that d𝑦 by d𝑥 is simply the reciprocal of d𝑥 by d𝑦.

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