Video Transcript
The equation of a plane has general form five π₯ plus six π¦ plus nine π§ minus 28 is equal to zero. What is its vector form?
In this question, weβre given the general form of the equation of the plane and we need to use this to determine the vector form of the equation of the plane. To answer this question, letβs start by recalling what we mean by the general form of the equation of a plane. Itβs the form ππ₯ plus ππ¦ plus ππ§ plus π is equal to zero, where π, π, π, and π are constants. And in particular, the vector π, π, π will be a normal vector to the plane. And since weβre given the general form of the equation of the plane, we can determine the normal vector to the plane as the coefficients of our variables. And we can also determine the value of π.
Letβs now recall the vector form of the equation of a plane. Itβs the form vector π§ dot vector π« is equal to a constant π prime, where the vector π§ is a normal vector to the plane. And thereβs something worth noting about the constants π prime and π. Thereβs a geometric interpretation of both of these constants. The constant π prime is a translation of our plane π prime units in the direction of the normal vector π§. However, the constant π is a translation of our plane negative π units in the direction of its normal vector. So if we set our normal vector π§ equal to the vector π, π, π, then we get that π prime will be equal to negative π.
And itβs worth noting there is a second nongeometric way of seeing this result. We just subtract π from both sides of the equation in our general equation of the plane. So weβll set our vector π§ to have components equal to the coefficients of the variables. Thatβs π§ as the vector five, six, nine. And then our constant π prime will be negative π. Thatβs negative one times negative 28, which is just 28. And then we substitute this vector and this constant into our vector form of the equation of a plane to get our final answer, which is that the vector form of the equation of the plane five π₯ plus six π¦ plus nine π§ minus 28 is equal to zero is the dot product between the vectors five, six, nine and π« is equal to 28.