### Video Transcript

Triangles π΄π΅πΆ and π΄ prime π΅
prime πΆ prime are similar. Work out the value of π₯. Work out the value of π¦.

In this question, we have two
triangles which weβre told are similar. We should remember that when we
have similar triangles, this means that corresponding pairs of angles are congruent
or equal and corresponding pairs of sides are in the same proportion. We can use this fact to help us
work out the values of π₯ and π¦. So letβs start with the first
question to find the value of π₯. When weβre working with similar
shapes, weβre usually given or can easily calculate the length of two corresponding
sides. In this diagram, weβre given the
lengths of two corresponding sides π΄π΅ and π΄ prime π΅ prime. These lengths are five and
three.

We could write this proportion as
π΄π΅ over π΄ prime π΅ prime. As we need to find the length of π₯
which is on the line segment π΄ prime πΆ prime, then the corresponding side will be
the line segment π΄πΆ. So the proportion of π΄π΅ over π΄
prime π΅ prime must be equal to the proportion of π΄πΆ over π΄ prime πΆ prime. Notice that we couldβve written
this proportionality statement with the numerators and denominators both
switched. But now all we need to do is fill
in the values of the lengths that weβre given. So we have five over three is equal
to 10 over π₯.

To solve for π₯, we can begin by
taking the cross product. And this gives us that five π₯ is
equal to 30. And then dividing both sides by
five, we would get that π₯ must be equal to six. And so thatβs the answer for the
first part of the question.

Letβs now look at the second part
of this question to find the value of π¦. This triangle will still have the
ratio of sides, the same as the proportion π΄π΅ over π΄ prime π΅ prime. But this time, letβs look at the
other two corresponding sides. These sides are π΅πΆ and π΅ prime
πΆ prime. Because we have side π΄π΅ on the
numerator, then side π΅πΆ must also be on the numerator, as itβs part of the same
triangle.

So π΄π΅ over π΄ prime π΅ prime must
be equal to π΅πΆ over π΅ prime πΆ prime. When we fill in the values, weβll
have five-thirds on the left-hand side. π΅πΆ is equal to seven, and π΅
prime πΆ prime is equal to π¦. When we take the cross product at
this time, weβll have five times π¦, which is five π¦, is equal to three times
seven, which is 21. Dividing both sides of this
equation by five gives us that π¦ is equal to 21 over five.

Weβve now fully answered the
question. π₯ is equal to six, and π¦ is equal
to 21 over five. Both of these values are lengths,
so the units of these would be length units.