Video Transcript
In the given figure, find vector
ππ.
We begin by recalling that the
vector between any two points, π΄ π₯ sub one, π¦ sub one, π§ sub one and π΅ π₯ sub
two, π¦ sub two, π§ sub two, is given by vector ππ, which has components π₯ sub
two minus π₯ sub one, π¦ sub two minus π¦ sub one, π§ sub two minus π§ sub one. In this question, we will begin by
finding the coordinates of points π΄ and π΅ from the figure. From the origin, point π΄ is six
centimeters in the positive π₯-direction. It is 12 centimeters in the
positive π¦-direction and finally five centimeters in the positive π§-direction. This means that point π΄ has
coordinates six, 12, five. Repeating this process for point
π΅, from the origin, we travel 12 centimeters in the positive π¦-direction and five
centimeters in the positive π§-direction. This means that point π΅ has
coordinates zero, 12, five.
We can now calculate vector ππ by
subtracting the components of the corresponding position vectors. ππ is equal to zero minus six, 12
minus 12, five minus five. This is equal to negative six,
zero, zero. This is the vector ππ from the
diagram.
We could also have found this
directly from the diagram. To travel from point π΄ to point
π΅, we move six centimeters in the negative π₯-direction. This means that the π₯-component in
our vector will be equal to negative six. As we donβt move in the π¦- or
π§-directions when traveling from point π΄ to point π΅, these will have components
equal to zero. This confirms that vector ππ is
equal to negative six, zero, zero.