Video Transcript
In the closed interval negative one
to two, determine the absolute maximum and minimum values of the function ๐ of ๐ฅ
equals four ๐ฅ squared plus three ๐ฅ minus seven if ๐ฅ is less than or equal to one,
six ๐ฅ minus five if ๐ฅ is greater than one. And round them to the nearest
hundredth.
In order to find absolute maximum
and minimum values of a function, we need to consider a couple of things. We need to look for any critical
points of the function. Remember, these are points where
the first derivative is equal to zero. A critical point can indicate a
relative maximum and a relative minimum. And these of course could also be
absolute extrema. We also need to consider the end
points of the function.
So what weโre going to do is begin
by finding the first derivative of our function. Now, our function is piecewise. So weโre going to differentiate
each expression with respect to ๐ฅ. Letโs begin with the expression
four ๐ฅ squared plus three ๐ฅ minus seven. The derivative of four ๐ฅ squared
with respect to ๐ฅ is two times four ๐ฅ, which is eight ๐ฅ. The derivative of three ๐ฅ is
three. And the derivative of negative
seven is zero. And thatโs for values of ๐ฅ less
than or equal to one.
Next, we differentiate six ๐ฅ minus
five with respect to ๐ฅ. Well, the derivative of six ๐ฅ
minus five is simply six. So we see that the first derivative
is either equal to ๐ฅ plus three if ๐ฅ is less than or equal to one or six if ๐ฅ is
greater than one. And actually, if we look carefully,
we see that the expression six cannot be equal to zero for any values of ๐ฅ. This indicates to us there are no
critical points in this part of the function. But we will set eight ๐ฅ plus three
equal to zero and solve for ๐ฅ. By subtracting three from both
sides and then dividing through by eight, we find that ๐ฅ equals negative
three-eighths. So we have a critical point when ๐ฅ
is equal to negative three-eighths.
So weโre going to do a number of
things. Weโre going to evaluate the
function at this critical point. Thatโs ๐ of negative
three-eighths. Weโll evaluate it at the lower and
upper end of our interval. Thatโs ๐ of negative one and ๐ of
two. And weโll evaluate it here when ๐ฅ
is equal to one. This is the end point of each bit
of the function. Now, when ๐ฅ is equal to negative
three-eighths, it is indeed less than or equal to one. So we use the first bit of our
function to evaluate ๐ of negative three-eighths. Itโs four times negative three
eighths squared plus three times negative three-eighths minus seven. Thatโs negative 7.5625.
When ๐ฅ is equal to negative one,
we use the same bit of the function. So we get four times negative one
squared plus three times negative one minus seven, which is negative six. Now, negative six is greater than
negative 7.5625. So when ๐ฅ is equal to negative
one, we absolutely canโt have an absolute minimum. But we could still have an absolute
maximum. Weโre now going to test ๐ of
two. When ๐ฅ is equal to two, this is
obviously greater than one. So weโre going to use the second
part of our function. Thatโs six times two minus five,
which is equal to seven.
Finally, we just need to check when
๐ฅ is equal to one. We go back to the first part of our
function because this is defined for values of ๐ฅ less than or equal to one. We get four times one squared plus
three times one minus seven, which is equal to zero. Well, if we look carefully, we see
that the smallest value we have over our interval is negative 7.5625. And the largest value we get is
seven. We round negative 7.5625 correct to
the nearest hundredth.
And we find that the absolute
maximum value of our function is seven. And the absolute minimum is
negative 7.56.