### Video Transcript

When opening a door, you push on it perpendicularly with a force of 55.0 newtons at a distance of 0.850 meters from the hinges. What torque are you exerting relative to the hinges?

The force applied weโre told is 55.0 newtons; weโll call that ๐น. Weโre also told that this force is applied at distance of 0.850 meters from the hinges; weโll call that distance ๐. If we were to draw a diagram, looking down on the door from above of the action going on, we would see that weโre applying the force ๐น perpendicularly to the door a distance of ๐ meters away from the doorโs hinge.

We want to solve for the torque that weโre exerting relative to the hinges, which weโll call ๐. To begin, we can recall the definition for torque. In general, the torque is equal to the cross-product of the radius ๐ with the applied Force ๐น.

When ๐ and ๐น are in the same plane as they are in our example, we can write a simplified version of this equation for torque. Torque is equal to ๐ times ๐น times the sin of the angle between them. In our case, ๐ and ๐น are at right angles to one another. So when we use this simplified equation for torque, since the sin of 90 degrees is equal to one, the equation simplifies to simply torque equals ๐ cross ๐น.

When we plug in for the given values of ๐ and ๐น and multiply them together, we find that the resulting torque is 46.8 newton meters. This is how much torque the force ๐น exerts relative to the hinges.