### Video Transcript

Solve π¦ equals two π₯ plus one divided by three π₯ plus four with an expression for
π₯ in terms of π¦.

Essentially, this means we need to take our equation and solve for π₯. So the first
thing that we should do is we should get rid of our denominator. The best way to do that is to
multiply both sides by your denominator of three π₯ plus four. Again, multiplying both sides by three π₯ plus four, weβll eliminate our denominator on the right-hand side of the equation. So we have three π₯ plus four times π¦ is equal to two π₯ plus one. Letβs go ahead and
use the distributive property on the left-hand side. So we will distribute π¦ to three π₯ and π¦ to four. When we say distribute,
that means weβre actually multiplying. We can see that weβve a three π₯π¦ term, a four π¦ term, and a two π₯ term.

Since we essentially are solving for π₯, letβs go ahead and get all of the terms
that have an π₯ in it on one side of the equation. So we will go ahead and subtract three π₯π¦ to both sides of the equation. On the left-hand side, the three π₯π¦s cancelled. And on the right, the three π₯π¦
cannot be combined with either of the two terms, two π₯ or one. So we just go ahead and just add it to
that side of the equation. Now when we say add, it is a negative, so itβs still a minus three π₯π¦.
Now letβs go ahead and move the plus one thatβs on the right-hand side of the equation over to
the left side. So letβs subtract one from both sides of the equation.

On the left-hand side, four π¦ and minus one cannot be combined. And on the right-hand
side, the ones cancelled. Now we can see on the right-hand side, weβre getting closer to just
having an π₯ on that side. Letβs go ahead and move this. So that way, we have some more room. So on the right-hand
side, we can take out a factor of π₯ since both terms have an π₯. So that turns into π₯ times two minus three π¦. So in order to isolate π₯, we can divide
both sides by two minus three π¦. On the right-hand side, the two minus three π¦s cancel. And on the left, we can
leave it.

Four π¦ minus one divided by two minus three π¦ does not reduce. This means our final
answer is: π₯ equals four π¦ minus one divided by two minus three π¦.