### Video Transcript

Given π΄ is equal to four, negative
seven, negative three, negative four, find its multiplicative inverse if
possible.

Remember, for a two-by-two matrix
π΄ which is equal to π, π, π, π, its inverse is given by the formula one over
the determinant of π΄ multiplied by π, negative π, negative π, π, where the
determinant of π΄ is found by subtracting the product of the top right and the
bottom left element from the product of the top left and the bottom right. Thatβs π multiplied by π minus π
multiplied by π.

Notice this means if the
determinant of the matrix π΄ is zero, the inverse cannot exist since one divided by
the determinant of π΄ becomes one divided by zero, which is undefined. Letβs substitute the values for our
matrix into the formula for the determinant of π΄: π is four, π is negative seven,
π is negative three, and π is negative four. So the determinant of π΄ is π
multiplied by π, thatβs four multiplied by negative four, minus π multiplied by
π, thatβs negative seven multiplied by negative three.

Four multiplied by negative four is
negative 16, and negative seven multiplied by negative three is just 21. So this becomes negative 16 minus
21, which is negative 37. Since the determinant of π΄ is not
zero, the inverse of π΄ does exist. And now that we have that
determinant, we can substitute everything we know into the formula for the inverse
of π΄.

One over the determinant of π΄ is
one over negative 37 or negative one thirty-seventh. Then we switch the value for π and
π. So we get negative four in the top
left corner and four in the bottom right. We multiply the elements that we
named π and π by negative one. And that gives us seven in the top
right corner and three in the bottom left.

The inverse of π΄ is therefore
negative one thirty-seventh multiplied by negative four, seven, three, four.