### Video Transcript

A rectangle with dimensions π₯
minus π¦ and π₯ plus π¦ plus one is cut out from a larger rectangle with dimensions
two π₯ plus π¦ plus three and two π₯ plus π¦. Find a simplified expression for
the shaded area.

We can find an expression for the
shaded area by finding the area of the larger rectangle and subtracting the area of
the smaller rectangle from the area of the larger rectangle. We recall the area of a rectangle
is found by multiplying its length times its width. Letβs start by expanding and
simplifying the expression for the area of the larger rectangle, two π₯ plus π¦ plus
three times two π₯ plus π¦. We can do this by distributing the
trinomial over each term in the binomial. So, we have two π₯ times two π₯
plus π¦ plus three plus π¦ times two π₯ plus π¦ plus three.

Then, we can distribute the
monomials over the trinomials. Distributing two π₯ over two π₯
plus π¦ plus three gives four π₯ squared plus two π₯π¦ plus six π₯. And distributing π¦ over the same
trinomial gives two π₯π¦ plus π¦ squared plus three π¦. We can add these expressions
together and collect like terms to find the area of the larger rectangle, four π₯
squared plus four π₯π¦ plus π¦ squared plus six π₯ plus three π¦.

Now, letβs clear some space to find
the area of the smaller rectangle. For the smaller rectangle, we have
dimensions π₯ plus π¦ plus one and π₯ minus π¦. So, the expression for its area
comes from the product of these two expressions. We can do this, once again, by
distributing the trinomial over each term in the binomial. So, we have π₯ times π₯ plus π¦
plus one minus π¦ times π₯ plus π¦ plus one. Then, we can distribute the
monomials over the trinomials. Distributing π₯ over π₯ plus π¦
plus one gives π₯ squared plus π₯π¦ plus π₯. And distributing negative π¦ over
π₯ plus π¦ plus one gives negative π₯π¦ minus π¦ squared minus π¦. We can then add these expressions
together and collect like terms to find the area of the smaller rectangle, resulting
in the expression π₯ squared minus π¦ squared plus π₯ minus π¦.

Now we need to subtract the area of
the smaller rectangle from the area of the larger rectangle to find the area of the
shaded region. We must be careful on this step to
subtract all the terms of the second polynomial, not just the first term. We can do this by distributing the
negative through each term and then collecting the like terms. Thus, we subtract π₯ squared, add
π¦ squared, subtract π₯, and add π¦ to the first expression. We can use a vertical method to
stack the like terms, resulting in three π₯ squared plus four π₯π¦ plus two π¦
squared plus five π₯ plus four π¦. This is the simplified expression
for the shaded region, which we found by subtracting the area of the smaller
rectangle from the area of the larger rectangle.