Suppose that 𝑓 is
differentiable. What is the derivative of 𝑥 cubed
𝑓 of 𝑥?
So if we take a look at 𝑥 cubed 𝑓
of 𝑥, what this is is 𝑥 cubed multiplied by a function. So how are we going to
differentiate this? Well to differentiate this, what
we’re gonna use is something called the product rule. And we’re gonna use that because
the product rule tells us that if we have 𝑦 is equal to 𝑢𝑣, so if we’re looking
at two things multiplied together like here we have 𝑥 cubed and 𝑓 of 𝑥, then the
derivative or 𝑑𝑦 𝑑𝑥 is gonna be equal to 𝑢 𝑑𝑣 𝑑𝑥 plus 𝑣 𝑑𝑢 𝑑𝑥. So 𝑑𝑢 multiplied by the
derivative of 𝑣 plus 𝑣 multiplied by the derivative of 𝑢.
So in our expression, what we have
is 𝑥 cubed, this is gonna be our 𝑢, and 𝑓 of 𝑥, this is gonna be our 𝑣. Therefore, if 𝑢 was equal to 𝑥
cubed, 𝑑𝑢 𝑑𝑥 is gonna be equal to three 𝑥 squared. And just to remind us how we got
that, we got the exponent, which is three, and then we multiply it by the
coefficient, which is one, so three multiplied by one. And then we’ve got 𝑥 to the power
of, and then you subtract one from the exponent. So three minus one gives us two, so
it gives us our three 𝑥 squared. And then if 𝑣 is our function of
𝑥, then 𝑑𝑣 𝑑𝑥 is gonna be the derivative of this function of 𝑥, which I’ve
shown using 𝑓 prime of 𝑥.
So this is gonna give us the
derivative is equal to 𝑥 cubed 𝑓 prime of 𝑥 or the derivative of 𝑓 of 𝑥. And that’s because that was our 𝑢
multiplied by our 𝑑𝑣 𝑑𝑥 plus 𝑣 𝑑𝑢 𝑑𝑥, so three 𝑥 squared multiplied by 𝑓
of 𝑥. And that’s because our 𝑣 was 𝑓 of
𝑥 and our 𝑑𝑢 𝑑𝑥 was three 𝑥 squared. And therefore, we can write this
the other way round if we want to have it in increasing powers of 𝑥. But we can suppose that if 𝑓 is
differentiable, the derivative of 𝑥 cubed 𝑓 of 𝑥 is going to be three 𝑥 squared
𝑓 of 𝑥 plus 𝑥 cubed of the derivative of 𝑓 of 𝑥.