Video Transcript
Madison is skip counting to
find five times four. Four, eight, 12, 16, 20. How else could she skip count
to find five times four? Two, four, six, eight, 10, 12,
14, 20. Two, four, eight, 12, 16,
20. Five, 10, 15, 20. Five, seven, 10, 14, 20. Which other equation would this
solve? Four times four, four plus
five, five times five, or four times five.
In this question, Madison is
skip counting to find five times four. She counted in fours five
times. Four, eight, 12, 16, 20. We have to find another way to
skip count to find five times four. Madison skip counted in fours
five times to find five times four. What would happen if we changed
the order of the two numbers we’re multiplying? Instead of finding five times
four, we could find four times five. We’d need to count in fives
four times. Five, 10, 15, 20.
The product is the same. So although our first possible
answer takes us to the number 20, it doesn’t show five times four or four times
five. Two, four, six, eight, 10, 12,
14, 20. It looks like someone was skip
counting in twos, but they did leave out the numbers 16 and 18. So this isn’t a way of skip
counting to show five times four. Two, four, eight, 12, 16,
20. This doesn’t show five times
four. We start off by skip counting
in twos and then in fours. So we can eliminate this
answer. Five, 10, 15, 20. This is four times five, skip
counting in fives four times. This is another way Madison
could skip count to find five times four.
Which other equation would this
solve? Four times four, four plus
five, five times five, or four times five. If five times four equals 20,
then four times five equals 20. This question is all about the
commutative property of multiplication. It doesn’t matter which order
we multiply two factors; the product stays the same. If five times four is 20, then
four times five is 20.
