# Question Video: Understanding the Commutative Property of Multiplication when Skip Counting to Solve Equations

Madison is skip counting to find 5 × 4. 4, 8, 12, 16, 20. How else could she skip count to find 5 × 4? [A] 2, 4, 6, 8, 10, 12, 14, 20 [B] 2, 4, 8, 12, 16, 20 [C] 5, 10, 15, 20 [D] 5, 7, 10, 14, 20 Which other equation would this solve? [A] 4 × 4 [B] 4 + 5 [C] 5 × 5 [D] 4 × 5

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### Video Transcript

Madison is skip counting to find five times four. Four, eight, 12, 16, 20. How else could she skip count to find five times four? Two, four, six, eight, 10, 12, 14, 20. Two, four, eight, 12, 16, 20. Five, 10, 15, 20. Five, seven, 10, 14, 20. Which other equation would this solve? Four times four, four plus five, five times five, or four times five.

In this question, Madison is skip counting to find five times four. She counted in fours five times. Four, eight, 12, 16, 20. We have to find another way to skip count to find five times four. Madison skip counted in fours five times to find five times four. What would happen if we changed the order of the two numbers we’re multiplying? Instead of finding five times four, we could find four times five. We’d need to count in fives four times. Five, 10, 15, 20.

The product is the same. So although our first possible answer takes us to the number 20, it doesn’t show five times four or four times five. Two, four, six, eight, 10, 12, 14, 20. It looks like someone was skip counting in twos, but they did leave out the numbers 16 and 18. So this isn’t a way of skip counting to show five times four. Two, four, eight, 12, 16, 20. This doesn’t show five times four. We start off by skip counting in twos and then in fours. So we can eliminate this answer. Five, 10, 15, 20. This is four times five, skip counting in fives four times. This is another way Madison could skip count to find five times four.

Which other equation would this solve? Four times four, four plus five, five times five, or four times five. If five times four equals 20, then four times five equals 20. This question is all about the commutative property of multiplication. It doesn’t matter which order we multiply two factors; the product stays the same. If five times four is 20, then four times five is 20.