If a single digit is selected at random from the number 224,839,287, what is the probability of the digit being even?
We begin by recalling that the probability of an event is the chance or likelihood of it occurring. We can write the probability of an event as a fraction, decimal, or percentage. And it can be calculated by dividing the number of successful outcomes by the total number of possible outcomes. In this question, we’re selecting a single digit from the nine-digit number, 224,839,287. Since we are selecting a digit at random, it will be equally likely that we select each of the digits.
We are trying to calculate the probability that the digit is even. The even digits are two, four, six, eight, and zero. Of the nine digits, we see that six of them are even. There are three twos, one four, and two eights. The digits three, nine, and seven are odds. The probability that the digit is even is therefore equal to six over nine or six-ninths. As both the numerator and denominator are divisible by three, this can be simplified to two-thirds.
When a single digit is selected at random from the number 224,839,287, the probability the digit is even is two-thirds.