Question Video: Finding the Parametric Equation of a Line through the Midpoint between Two Points and Given a Direction Vector | Nagwa Question Video: Finding the Parametric Equation of a Line through the Midpoint between Two Points and Given a Direction Vector | Nagwa

Question Video: Finding the Parametric Equation of a Line through the Midpoint between Two Points and Given a Direction Vector Mathematics • Third Year of Secondary School

Give the parametric equation of the line that passes through the midpoint between 𝑝₁ = (1, 2, 3) and 𝑝₂ = (3, 6, −5) with direction vector 〈−1, 2, 5〉.

02:30

Video Transcript

Give the parametric equation of the line that passes through the midpoint between 𝑝 one equals one, two, three and 𝑝 two equals three, six, negative five with direction vector negative one, two, five.

We’re given that a line passes through the midpoint between the two points 𝑝 one and 𝑝 two and has a direction vector with components negative one, two, and five. Now, we know that the parametric equations of a line in space are a nonunique set of three equations: 𝑥 equals 𝑥 sub 𝐴 plus 𝑡𝑙, 𝑦 equals 𝑦 sub 𝐴 plus 𝑡𝑚, and 𝑧 equals 𝑧 sub 𝐴 plus 𝑡𝑛. And that’s where 𝐴 is a point on the line with coordinates 𝑥 sub 𝐴, 𝑦 sub 𝐴, and 𝑧 sub 𝐴; the vector with components 𝑙, 𝑚, 𝑛 is a direction vector of the line; and 𝑡 is a real parameter between negative and positive ∞.

We’ve been given the direction vector for the line. So we can straightaway write down the components 𝑙, 𝑚, and 𝑛. That’s 𝑙 equals negative one, 𝑚 equals two, and 𝑛 equals five. And to calculate a point on the line, we can use the midpoint formula for the midpoint between 𝑝 one and 𝑝 two. This is just the point whose coordinates are the averages of the 𝑥-, 𝑦-, and 𝑧-coordinates, respectively, of the two given points. So, with 𝑝 one equals one, two, three and 𝑝 two equals three, six, negative five, our midpoint has coordinates one plus three over two, two plus six over two, and three plus negative five over two. That’s four over two, eight over two, and negative two over two, which is the point with coordinates two, four, and negative one.

So now making some space, we have our direction vector with components negative one, two, and five and the point on the line with coordinates 𝑥 sub 𝐴 equals two, 𝑦 sub 𝐴 equals four, and 𝑧 sub 𝐴 equals negative one. And now substituting these into the expressions for the parametric equations of the line, we have 𝑥 equals two, which is 𝑥 sub 𝐴, plus negative one, which is 𝑙, times 𝑡. That’s 𝑥 equals two minus 𝑡. 𝑦 equals four, that’s 𝑦 sub 𝐴, plus two, which is 𝑚, times 𝑡. And 𝑧 equals negative one, 𝑧 sub 𝐴, plus five, which is 𝑛, times 𝑡.

So the parametric equations of the line passing through the midpoint of 𝑝 one and 𝑝 two with direction vector negative one, two, five is 𝑥 equals two minus 𝑡, 𝑦 equals four plus two 𝑡, and 𝑧 equals negative one plus five 𝑡.

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