### Video Transcript

Three particles are placed on a
line. Particle π΄ of mass four kilograms
is located at the origin; particle π΅ of mass six kilograms at nine, six; and
particle πΆ of mass 10 kilograms at six, four. Determine the coordinates of the
center of mass of the three particles.

We will begin by drawing the three
particles on a pair of coordinate axes. We are told that particle π΄ lies
at the origin. Particle π΅ lies at the point nine,
six. And particle πΆ lies at six,
four. This question asked us to find the
center of mass of the three particles. We recall that the center of mass
is in effect the average position of all of the mass in a system. We can calculate the exact position
of the center of mass of a system of particles by finding the average position of
those particles weighted according to their mass.

Specifically, we can calculate the
coordinates of the center of mass of a system consisting of particles in
two-dimensional space using these two equations. Firstly, the π₯-coordinate of the
center of mass, written COM sub π₯, can be found by adding together the product of
each particleβs mass and π₯-coordinate and dividing this quantity by the sum of all
the masses of the particles. In the same way, the π¦-coordinate
of the center of mass, written COM sub π¦, can be found by adding together the
product of each particleβs mass and π¦-coordinate and once again dividing by the sum
of all the masses of the particles.

Letβs begin by calculating the
π₯-coordinate of the center of mass in this question. On the numerator, we need to
multiply the mass of particle π΄ by the π₯-coordinate of particle π΄, multiply the
mass of particle π΅ by the π₯-coordinate of particle π΅, and multiply the mass of
particle πΆ by the π₯-coordinate of particle πΆ. We then find the sum of these three
values. On the denominator, we have the sum
of the masses of the three particles. Particle π΄ has a mass of four
kilograms and an π₯-coordinate of zero as it is located at the origin. Particle π΅ has a mass of six
kilograms and an π₯-coordinate of nine. Finally, particle πΆ has a mass of
10 kilograms and an π₯-coordinate of six.

The π₯-coordinate of the center of
mass is therefore equal to four multiplied by zero plus six multiplied by nine plus
10 multiplied by six divided by four plus six plus 10. This simplifies to 114 over 20,
which is equal to 5.7. The π₯-coordinate of the center of
mass is 5.7.

Letβs now consider the
π¦-coordinate. We calculate this in the same way,
except this time on the numerator we multiply the mass of each particle by its
corresponding π¦-coordinate. This simplifies to 76 over 20,
which is equal to 3.8. The π¦-coordinate of the center of
mass is 3.8.

We can therefore conclude that the
center of mass of the three particles has coordinates 5.7, 3.8 as shown.