Question Video: Evaluating Exponential Equations Involving Exponential Growth | Nagwa Question Video: Evaluating Exponential Equations Involving Exponential Growth | Nagwa

Question Video: Evaluating Exponential Equations Involving Exponential Growth Mathematics • Second Year of Secondary School

A mathematical model predicts that the population of a city, 𝑥 million, will be given by the formula 𝑥 = 2(1.22)^𝑛, where 𝑛 is the number of years from now. What does the model predict the population will be in 2 years’ time?

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Video Transcript

A mathematical model predicts that the population of a city, 𝑥 million, will be given by the formula 𝑥 is equal to two multiplied by 1.22 to the power 𝑛, where 𝑛 is the number of years from now. What does the model predict the population will be in two years’ time?

Let’s begin by considering the formula we’re given that models the population of a city. It states that 𝑥, the population in million, is equal to two multiplied by 1.22 to the power of 𝑛, where 𝑛 is the number of years from now. We are asked to predict the population in two years’ time.

To do this, we will substitute 𝑛 equals two. 𝑥 is therefore equal to two multiplied by 1.22 squared. We could type this directly into the calculator. However, it is worth noting that 1.22 squared is equal to 1.22 multiplied by 1.22. We could work this out by multiplying 1.22 by one, 0.2, and 0.02 and then finding the sum of these three answers.

Firstly, 1.22 multiplied by one is simply 1.22. Multiplying 1.22 by 0.2 gives us 0.244. And multiplying 1.22 by 0.02 gives us 0.0244. The sum of these three products is 1.4884, and this is the value of 1.22 squared. The population 𝑥 is equal to two multiplied by this, which is equal to 2.9768. The model predicts that the population in the city in two years’ time will be 2.9768 million, which could also be written as 2,976,800.

It is important to note that we could use this model to predict the population over a longer period of time. For example, if we wanted to predict the population in 10 years’ time, we could substitute 𝑛 equals 10 into the formula. This could be repeated for any number of years moving forwards.

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