### Video Transcript

Calculate the value of Kp in the
reaction shown, given the following partial pressures: P(N₂) equal to 0.4
atmospheres, P(O₂) equal to two atmospheres, and P(NO₂) equal to four
atmospheres.

N₂ gas plus 2O₂ gas is in
equilibrium with 2NO₂ gas. Kp is the equilibrium constant. Kp is defined as the product of the
partial pressures of the products raised to their stoichiometric coefficients
divided by the same for the reactants. This is equal to the partial
pressure of nitrogen dioxide squared divided by the partial pressure of nitrogen
multiplied by the partial pressure of oxygen squared. This is equal to four squared
divided by 0.4 multiplied by two squared. This is equal to 10. So this is what you would need to
write, and here is our answer.