Question Video: Finding the Height of a Rhombus given the Lengths of Its Base and Diagonals | Nagwa Question Video: Finding the Height of a Rhombus given the Lengths of Its Base and Diagonals | Nagwa

Question Video: Finding the Height of a Rhombus given the Lengths of Its Base and Diagonals Mathematics • Second Year of Preparatory School

In the rhombus 𝐴𝐵𝐶𝐷, the side length is 8.5 cm, and the diagonal lengths are 13 cm and 11 cm. Find the length of 𝐷𝐹. Round your answer to the nearest tenth.

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Video Transcript

In the rhombus 𝐴𝐵𝐶𝐷, the side length is 8.5 centimeters and the diagonal lengths are 13 centimeters and 11 centimeters. Find the length of 𝐷𝐹. Round your answer to the nearest tenth.

We have two formulas for the area of a rhombus. The first tells us that the area is equal to half the product of the diagonals. Let’s substitute in the diagonal lengths that we have been given. 11 times 13 divided by two equals 71.5 square centimeters. The second rhombus area formula tells us that the area of the rhombus is equal to its side length times its perpendicular height. The perpendicular height of this rhombus is 𝐷𝐹, which is equal to 𝐷𝐸, because triangles 𝐷𝐶𝐸 and 𝐴𝐷𝐹 are congruent. Substituting in the side length of 8.5 and the area of 71.5 that we have just calculated, we have 71.5 equals 8.5 times 𝐷𝐹. Rearranging, we find that the length of 𝐷𝐹 is 71.5 divided by 8.5, which is 8.4 centimeters to the nearest tenth.

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