Question Video: Determining the Product of the Reaction between 4-Chlorobenzoic Acid and Ethanol | Nagwa Question Video: Determining the Product of the Reaction between 4-Chlorobenzoic Acid and Ethanol | Nagwa

Question Video: Determining the Product of the Reaction between 4-Chlorobenzoic Acid and Ethanol Chemistry • Third Year of Secondary School

Consider the reaction. What product is formed?

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Video Transcript

Consider the following reaction. What product is formed?

In this reaction, a compound containing an aryl halide and a carboxylic acid is reacted with an alcohol in the presence of hydrochloric acid, an acid catalyst. Our goal is to determine the product formed from this reaction. Let’s remove the question and answer choices for now to give us room to discuss this reaction.

The first thing we need to determine is which functional group will react with the alcohol under these conditions. Under certain conditions, alcohols can react with organohalides. For a reaction to occur, the alcohol must first be treated with a strong base, like sodium amide, to produce an alkoxide. Then, the alkoxide can be reacted with an organohalide, like an alkyl halide. The major product of this reaction is an ether. This reaction scheme is unbalanced and only shows the reactants, reagents, and major products of each step of the reaction.

This overall reaction is known as the Williamson ether synthesis. The Williamson ether synthesis is a substitution reaction between an organohalide and an alkoxide to form an ether. There are two main reasons why this reaction is not the reaction involved in this question. The first reason is that Williamson ether synthesis requires a strong base, but the reaction given in the question uses a strong acid catalyst. So, the first step of Williamson either synthesis would not be able to occur. The second reason is that during Williamson ether synthesis, the bond between the halogen and the rest of the organic molecule must break in order to form the ether. The bond between the chlorine and the benzene ring in an aryl halide is very strong due to resonance and is extremely unlikely to break under these reaction conditions.

With this information in mind, we have determined that a reaction between the aryl halide and the alcohol is extremely unlikely to occur. So, we should focus our attention on the reaction between a carboxylic acid and an alcohol in the presence of an acid catalyst. When a carboxylic acid and an alcohol react in the presence of an acid catalyst, the alkoxy group of the alcohol replaces the hydroxy group of the carboxylic acid. The products of this reaction are an ester and water. This reaction is an example of esterification, a type of chemical reaction where an ester is formed. More specifically, the esterification of a carboxylic acid with an alcohol in the presence of an acid catalyst is called Fischer esterification.

With this information in mind, let’s return to the reaction given in the question. We know that during Fischer esterification, the alkoxy portion of the alcohol will replace the hydroxy group of the carboxylic acid. The rest of the molecule shown here in blue will remain unchanged. The two products of this reaction are a molecule containing both an aryl halide and an ester, and the second product is water.

Now that we’ve determined the products of this reaction, let’s take another look at the answer choices. We can see that the answer choice which matches the product that we drew is answer choice (B). Thus, the product formed from the given reaction is answer choice (B).

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