Question Video: Using Proportions to Form and Solve Linear Equations | Nagwa Question Video: Using Proportions to Form and Solve Linear Equations | Nagwa

Question Video: Using Proportions to Form and Solve Linear Equations Mathematics

Julie starts with the numbers 5 and 12. If she adds a number π‘˜ to each of her numbers, the ratio of the resulting numbers is 23 : 24. Find the value of π‘˜.

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Video Transcript

Julie starts with the numbers five and 12. If she adds a number π‘˜ to each of her numbers, the ratio of the resulting numbers is 23 to 24. Find the value of π‘˜.

Let’s begin by considering the ratio of the numbers at the start of this problem. To begin with, the numbers are in a ratio five to 12. Remember, order here is important. Then we’re told that she adds some number π‘˜ to each of her numbers. So her first number five becomes five plus π‘˜, and her second number 12 becomes 12 plus π‘˜. This means the new ratio of these numbers can be represented as five plus π‘˜ to 12 plus π‘˜.

But remember, the question told us that the ratio of these resulting numbers is in fact 23 to 24. So five plus π‘˜ to 12 plus π‘˜ is in fact equal to 23 to 24. And whilst this might look quite nasty, this now means we can create a single equation in terms of π‘˜. Since these ratios are equal, if we divide the left-hand side of the first ratio by the right-hand side of the first ratio, this will be equal to dividing the left-hand side of the second ratio by the right-hand side of the second.

In other words, five plus π‘˜ over 12 plus π‘˜ is equal to 23 over 24. We’re going to now need to solve this equation for π‘˜. And to do so, we need to get rid of these fractions. So we’re going to multiply both sides of the equation by 12 plus π‘˜ and by 24. When we do, on the left-hand side, we get 24 times five plus π‘˜, and on the right, 23 times 12 plus π‘˜.

Our next job will be to distribute these parentheses. 24 times five plus π‘˜ is 120 plus 24π‘˜. And 23 times 12 plus π‘˜ is 276 plus 23π‘˜. Since we’re solving for π‘˜, we need to find a way to make it the subject. Let’s subtract 23π‘˜ from both sides. That gives us 120 plus π‘˜ equals 276. And we can now see that there’s just one more step to help us find the value of π‘˜; we need to subtract 120 from both sides. 276 minus 120 is 156. And so we have the value π‘˜ that Julie added to each of her numbers. It was 156.

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