### Video Transcript

Consider the two vectors π© equals
two π’ plus three π£ and πͺ equals six π’ plus four π£. Calculate π© dot πͺ.

This representation here of these
two vectors tells us that weβre to calculate their scalar or dot product. And we see weβre given the two
vectors π© and πͺ in their component form. So, we can start off by recalling
that the scalar product of two vectors by their components is equal to the
π₯-component of the first vector times the π₯-component of the second vector. Added to the π¦-component of the
first vector times the π¦-component of the second. In this equation, weβve called our
vectors π and π, but those are just general names for any vectors that lie in the
π₯π¦-plane.

In this example, what we want to
calculate is π© dot πͺ. And to do it, we can follow this
prescription for combining the components of these vectors. First, we take the π₯-component of
our first vector, thatβs π©, and the π₯-component of that vector is two. And we multiply this by the
π₯-component of our second vector. That second vector is πͺ and that
π₯-component is six. So, we have two times six. And to that, we add the
π¦-component of our first vector. That first vector is π© and that
π¦-component is three multiplied by the π¦-component of our second vector. That second vector is πͺ and that
π¦-component is four.

So what we have then is π© dot πͺ
is equal to two times six plus three times four. Two times six is 12 and so is three
times four. So, our final answer is 24. And notice that, indeed, this
answer is a scalar quantity. It has a magnitude but no
direction.