Question Video: Using the Summation Property of Combinations to Solve Problems | Nagwa Question Video: Using the Summation Property of Combinations to Solve Problems | Nagwa

Question Video: Using the Summation Property of Combinations to Solve Problems Mathematics

Find the value of 5C0 + 5C1 + 5C2+ ... + 5C5.

02:07

Video Transcript

Find the value of five choose zero plus five choose one plus five choose two all the way up to five choose five.

To answer this question, we’re going to recall two facts. π‘›πΆπ‘Ÿ or 𝑛 choose π‘Ÿ is found by dividing 𝑛 factorial by π‘Ÿ factorial times 𝑛 minus π‘Ÿ factorial. But we also know that combinations have symmetry such that 𝑛 choose π‘Ÿ is equal to 𝑛 choose 𝑛 minus π‘Ÿ.

Now, let’s look at all of the terms in our summation. We can see that 𝑛 here is going to be equal to five. And so let’s begin by evaluating five choose zero. In this case, π‘Ÿ is equal to zero. So five choose zero is five factorial over zero factorial times five minus zero factorial. Except, zero factorial is simply one. So we get five factorial divided by five factorial, which must also be equal to one. Due to this symmetry, we know that this must also be equal to five choose five. And so we see that five choose zero and five choose five are both equal to one.

We’re now going to work out five choose one. That’s five factorial over one factorial times five minus one factorial. One factorial is also one. So we get five factorial over four factorial. But since five factorial is five times four times three and so on, we can actually write it as five times four factorial. This means we can divide through by four factorial, and we find that five choose one is equal to five. And then using the symmetry, we find that five choose four is also equal to five.

We’re now going to evaluate five choose two and five choose three. For five choose two, we get five factorial over two factorial times five minus two factorial, which gives us 10. Since there’s this symmetry, we know this is also equal to five choose three. And so this means our sum is one plus five plus 10 plus 10 plus five plus one, which is equal to 32.

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