Question Video: Determining the Polarity of the Bond and Overall Molecule of Molecular Nitrogen | Nagwa Question Video: Determining the Polarity of the Bond and Overall Molecule of Molecular Nitrogen | Nagwa

Question Video: Determining the Polarity of the Bond and Overall Molecule of Molecular Nitrogen Chemistry • Second Year of Secondary School

Fill in the blanks: N₂ is a _ molecule and has a _ bond.

03:02

Video Transcript

Fill in the blanks. N2 is a blank molecule and has a blank bond. (A) Nonpolar, nonpolar. (B) Polar, polar. (C) Nonpolar, polar. Or (D) polar, nonpolar.

In this question, we want to know about the polarity of a nitrogen molecule and the bond within it. To determine the polarity of a bond, we can reference the electronegativity of the atoms. The electronegativity of an atom is its tendency to attract bonding pairs of electrons from a chemical bond. The absolute difference of the electronegativity values can tell us about the polarity of the bond. 𝐸 one and 𝐸 two are the electronegativity values of the two bonded elements. The electronegativity values we will use will be the unitless values from the Pauling scale.

By calculating the difference of electronegativities, we can identify the bond type as either pure covalent, nonpolar covalent, polar covalent, or ionic. An electronegativity difference of zero denotes a pure covalent bond. For example, diatomic hydrogen has a pure covalent bond since the two hydrogens have the same electronegativity, and thus the difference is zero.

Nonpolar covalent bonds have an electronegativity difference of less than 0.4. For example, the carbon-to-hydrogen bonds in methane have an absolute electronegativity difference of 0.35. This means methane contains nonpolar covalent bonds.

Polar covalent bonds have a range of electronegativity differences between 0.4 and approximately 1.7. For example, the bond in hydrogen chloride has an electronegativity difference of 0.96. This means it contains a polar covalent bond.

A bond is considered ionic when it has an electronegativity difference greater than approximately 1.7. For example, bonds in sodium fluoride have electronegativity differences of 3.05. So it contains ionic bonds.

There are only two nitrogen atoms in the nitrogen molecule, with a triple bond between them. Because the atoms in the bond are the same element, the electronegativity difference will be zero. We can calculate this using the electronegativity of nitrogen, which is 3.04. The absolute electronegativity difference is the absolute value of 3.04 minus 3.04, which equals zero.

With bonding only occurring between two atoms in the molecule, the molecule overall is also nonpolar due to the even distribution of charge. So the correct answer is (A) nonpolar, nonpolar. We can now fill in the blanks. N2 is a nonpolar molecule and has a nonpolar bond.

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