### Video Transcript

In this video, we will learn how to
calculate the sum of the terms in an arithmetic sequence with a definite number of
terms. We will begin by recalling what we
mean by an arithmetic sequence and arithmetic series.

The list of numbers written in a
definite order is called a sequence. In an arithmetic sequence, the
difference between one term and the next is a constant. This is known as the common
difference and is denoted by the letter π. The first term of an arithmetic
sequence π sub one is usually just written as π. The second term π sub two will
therefore be equal to π plus π. To get to the third term, we will
need to add π again, so π sub three is equal to π plus π plus π. This can be simplified to π plus
two π. This pattern continues so that the
fourth term is π plus three π, the fifth term π plus four π, and so on.

We notice that the second term has
one π. The third term has two πβs. The fourth term would have three
πβs and so on. This means that the πth term would
have π minus one πβs. This leads us to the formula for
the general term of an arithmetic sequence π sub π is equal to π plus π minus
one multiplied by π. When dealing with a finite
sequence, as in this video, we can denote the last term as π. The sum of terms of an arithmetic
sequence is called an arithmetic series. This means that an arithmetic
series would be written in the form π plus π plus π plus π plus two π and so on
all the way up to π plus π minus one multiplied by π.

We will now use this information to
prove two formulae to calculate the sum of the first π terms of an arithmetic
sequence.

Find an expression for the sum of
an arithmetic sequence whose first term is π and whose common difference is π.

We are told in the question that
the first term of our arithmetic sequence is π and the common difference is π. We are trying to find an expression
for the sum of the first π terms which we will write as π sub π. This will be equal to the first
term π plus the second term π plus π and so on. We know that the πth term of any
arithmetic sequence is equal to π plus π minus one multiplied by π. This means that the penultimate
term is equal to π plus π minus two multiplied by π. We will call this equation one.

We will then reverse the order of
this sum, which we can do as addition is commutative. This gives us π sub π is equal to
π plus π minus one multiplied by π plus π plus π minus two multiplied by π and
so on and finally plus π plus π plus π. We will call this equation two. Adding equation one and equation
two gives us two multiplied by π sub π on the left-hand side. On the right-hand side, we will add
each pair of terms. Adding the first pair, we see that
π plus π is equal to two π. So we have two π plus π minus one
multiplied by π.

The second pair of terms have the
same sum as π plus π is equal to two π and π plus π minus two π is equal to π
minus one π. In fact, this will be true for each
of the pairs in our equations. Each pair of terms will sum to give
us two π plus π minus one multiplied by π. We have π of these terms, so we
can rewrite the right-hand side as π multiplied by two π plus π minus one
multiplied by π. Dividing both sides of our equation
by two gives us π sub π is equal to π over two multiplied by two π plus π minus
one multiplied by π. This is an expression for the sum
of an arithmetic sequence whose first term is π and whose common difference is
π.

We will now look at an alternative
formula for the sum of an arithmetic sequence.

Write an expression for the sum of
the first π terms of an arithmetic sequence with first term π and last term
π.

We know that the sum of the first
π terms of an arithmetic sequence can be calculated using the formula π over two
multiplied by two π plus π minus one multiplied by π, where π is the number of
terms, π is the first term, and π is the common difference. We also know that the πth term π
sub π is equal to π plus π minus one multiplied by π. We are told in this question that
π is the last term. Therefore, π is equal to π plus
π minus one multiplied by π. Since π plus π is equal to two
π, we can rewrite our formula for π sub π as π over two multiplied by π plus π
plus π minus one multiplied by π.

We know that the second part inside
the brackets π plus π minus one multiplied by π is equal to π. The sum of the first π terms of an
arithmetic sequence with first term π and last term π is therefore equal to π
over two multiplied by π plus π.

We will now briefly summarize the
formulae we will use for the remainder of this video. The πth term π sub π is equal to
π plus π minus one multiplied by π. The sum of the first π terms
written π sub π is equal to π over two multiplied by two π plus π minus one
multiplied by π. As weβre dealing with finite
sequences, there will be a last term π. This will be equal to π sub
π. Therefore, π sub π is also equal
to π over two multiplied by π plus π. We will now use these formulae to
solve problems involving finite arithmetic sequences.

Find the sum of the first 10 terms
of the arithmetic sequence whose first term is five and common difference is
eight.

We are told that the first term,
denoted by the letter π, is equal to five. The common difference π of our
arithmetic sequence is equal to eight. As we need to calculate the sum of
the first 10 terms, π is equal to 10. We know that the sum of the first
π terms of an arithmetic sequence, denoted π sub π, is equal to π over two
multiplied by two π plus π minus one multiplied by π. Substituting in our values of π,
π, and π, we can calculate π sub 10. This is equal to 10 divided by two
multiplied by two multiplied by five plus 10 minus one multiplied by eight. Two multiplied by five is equal to
10, and 10 minus one multiplied by eight is equal to 72. Multiplying 82 by five gives us
410.

The sum of the first 10 terms of
the arithmetic sequence whose first term is five and common difference is eight is
410.

We will now look at a similar
question where our terms are negative.

Find the sum of the terms of the
11-term arithmetic sequence whose first term is negative 92 and last term is
negative 102.

The first term π of our arithmetic
sequence is equal to negative 92, and the last term π is equal to negative 102. We are also told there are 11 terms
in the sequence. Therefore, π is equal to 11. We could use this information to
calculate the common difference π. However, in this question, it is
not required. We can calculate the sum of the
first π terms using the formula π over two multiplied by π plus π. Substituting in our values, we see
that π sub 11 is equal to 11 over two multiplied by negative 92 plus negative
102. 11 divided by two is equal to 5.5,
and negative 92 plus negative 102 is equal to negative 194. Multiplying these two values gives
us negative 1067.

The sum of the 11 terms in the
arithmetic sequence whose first term is negative 92 and last term is negative 102 is
negative 1067.

In our next question, we need to
find the sum of the first 10 terms of an arithmetic sequence given the πth
term.

Find the sum of the first 10 terms
of the sequence π sub π, where π sub π is equal to two π plus four.

There are a few ways of approaching
this problem. One way would be to calculate the
first and last terms of the sequence. As there are 10 terms, these are
denoted by π sub one and π sub 10. The first term will be equal to two
multiplied by one plus four. This is equal to six. The tenth term π sub 10 is equal
to two multiplied by 10 plus four. This is equal to 24. We can now use the formula π sub
π is equal to π over two multiplied by π plus π, where π is equal to six, the
first term, and π is equal to 24, the 10th or last term. π sub 10 is equal to 10 over two
multiplied by six plus 24. This simplifies to five multiplied
by 30, giving us an answer for the sum of the first 10 terms of the sequence of
150.

An alternative method would be to
have recognized our sequence is linear. Therefore, the common difference π
is equal to two, the coefficient of π. If π sub π is equal to two π
plus four, our sequence is six, eight, 10, and so on. We could then use the formula that
π sub π is equal to π over two multiplied by two π plus π minus one multiplied
by π. Substituting in our values here
gives us π sub 10 is equal to 10 over two multiplied by two multiplied by six plus
10 minus one multiplied by two. This simplifies to five multiplied
by 12 plus 18, which once again is equal to five multiplied by 30, which gives us an
answer of 150.

We will now look at one final
question.

Find, in terms of π, the sum of
the arithmetic sequence nine, 10, 11, and so on up to π plus eight.

There are two formulas that we can
use to calculate the sum of an arithmetic sequence. Firstly, π sub π is equal to π
over two multiplied by π plus π, where π is the first term and π is the last
term of the sequence. Secondly, π sub π is equal to π
over two multiplied by two π plus π minus one multiplied by π. Once again, π is the first term
and π is the common difference of the sequence. We can see that the first term π
is equal to nine and the last term π is π plus eight. π sub π is therefore equal to π
over two multiplied by nine plus π plus eight. Collecting like terms inside the
parentheses gives us π over two multiplied by π plus 17. This is the expression, in terms of
π, for the sum of the arithmetic sequence.

If we chose to use the other
formula, we can see from the sequence that the common difference is equal to
one. Substituting in our values of π
and π gives us π sub π is equal to π over two multiplied by two multiplied by
nine plus π minus one multiplied by one. The expression inside the brackets
simplifies to 18 plus π minus one. 18 minus one is equal to 17. Therefore, the expression, once
again, is π over two multiplied by π plus 17. This is the sum of the arithmetic
sequence nine, 10, 11, and so on all the way up to π plus eight.

We will now summarize the key
points from this video. We saw in this video that an
arithmetic sequence has first term π, last term π, and common difference π. The πth term of an arithmetic
sequence π sub π is equal to π plus π minus one multiplied by π. When dealing with a finite
arithmetic sequence, this will also be equal to the last term π. The sum of the terms of an
arithmetic sequence is called an arithmetic series. We can calculate this sum denoted
π sub π using one of two formulae, either π over two multiplied by two π plus π
minus one multiplied by π or π over two multiplied by π plus π. The formula that we choose will
depend on the information given in a particular question.