Question Video: Finding the Area of a Triangle Using the Relation between Triangles That Share the Same Base and Are between Parallel Lines | Nagwa Question Video: Finding the Area of a Triangle Using the Relation between Triangles That Share the Same Base and Are between Parallel Lines | Nagwa

Question Video: Finding the Area of a Triangle Using the Relation between Triangles That Share the Same Base and Are between Parallel Lines Mathematics • Second Year of Preparatory School

Given that the area of △𝑌𝐴𝐵 = 568 cm², find the area of △𝑋𝐶𝐷.

03:43

Video Transcript

Given that the area of triangle 𝑌𝐴𝐵 is equal to 568 square centimeters, find the area of triangle 𝑋𝐶𝐷.

In this question, we are given the area of a triangle and a figure and asked to determine the area of another triangle. To answer this question, we can begin by highlighting the triangle of known area and the triangle whose area we want to find on the diagram. At first, it may seem difficult to compare the areas of these two triangles directly, since there is little information to go on. Instead, let’s look at the information we are given in the figure.

We are given no congruent line segments in the figure. We are only given three parallel lines. However, we can recall a theorem for the equality of areas of triangles between parallel lines. We can recall that if two triangles share a base and the vertices that are opposite the base lie on a straight line that is parallel to the base, then the triangles must have the same areas. This is because the perpendicular distance between parallel lines remains constant. So, the perpendicular heights of the triangles will be equal. We can apply this result to several triangles in the figure.

First, we note that triangles 𝑌𝑋𝐷 and 𝑌𝑋𝐴 share the line segment 𝑌𝑋 as a base and the vertices opposite the base lie on a line parallel to the base. Therefore, we can apply this property to conclude that the area of triangle 𝑌𝑋𝐷 is equal to the area of triangle 𝑌𝑋𝐴. We can also apply this property to the triangles on the bottom of the figure. We can see that triangles 𝑌𝑋𝐶 and 𝑌𝑋𝐵 share line segment 𝑌𝑋 as a base and their vertices opposite the base lie on a line parallel to the base. Hence, the area of triangle 𝑌𝑋𝐶 is equal to the area of triangle 𝑌𝑋𝐵.

We can then note that each of these pairs of triangles combine to make the two larger triangles that we are interested in. In particular, the area of triangle 𝑌𝑋𝐷 added to the area of triangle 𝑌𝑋𝐶 gives us the area of triangle 𝑋𝐶𝐷. Similarly, the sum of the areas of triangles 𝑌𝑋𝐴 and 𝑌𝑋𝐵 is equal to the area of triangle 𝑌𝐴𝐵. Since these triangles are made up of two triangles of the same area with no overlap, they must have the same area. Hence, the area of triangle 𝑋𝐶𝐷 is also 568 square centimeters.

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