Question Video: Solving Quadratic Equations | Nagwa Question Video: Solving Quadratic Equations | Nagwa

Question Video: Solving Quadratic Equations Mathematics • Second Year of Preparatory School

Solve 2(𝑥 + 4)² = 162.

03:29

Video Transcript

Solve two times 𝑥 plus four squared is equal to 162.

In this question, we want to find the solutions to an equation. To do this, we want to isolate 𝑥 on one side of the equation by applying the same operations to both sides of the equation.

We can first note that we can divide both sides of the equation through by two to cancel the factor of two on the left-hand side of the equation. On the left-hand side of the equation, we are left with 𝑥 plus four all squared. And on the right-hand side of the equation, we have 162 over two, which is equal to 81. To isolate 𝑥 on the left-hand side of the equation, we can now note that we are squaring an expression for 𝑥 on the left-hand side of the equation. We can reverse this operation by taking square roots of both sides of the equation; however, we need to be careful.

When we are solving an equation by taking square roots, we need to be aware that there can be both positive and negative solutions. For instance, the equation 𝑦 squared equals 81 has two solutions, 𝑦 equals nine and 𝑦 equals negative nine, that is, the two numbers whose square is 81. Keeping this in mind, when we try to solve an equation by taking square roots, we always need to consider both the negative and positive root. This means that we have two cases, one for each root. Either 𝑥 plus four is equal to nine or 𝑥 plus four is equal to negative nine.

We can now solve each equation separately by isolating 𝑥. For the first equation, we subtract four from both sides of the equation to get that 𝑥 is equal to five. We can solve the second equation in the same way. We subtract four from both sides of the equation to obtain a second solution of 𝑥 equals negative 13. This is enough to answer the question. However, we can check our answers by substituting the values of 𝑥 back into the equation.

If we substitute 𝑥 equals five into the left-hand side of the equation, we get two times five plus four squared. We evaluate the sum inside the parentheses to get two times nine squared. We then find that nine squared is 81 and doubling this value gives 162, which is the same as the right-hand side of the given equation, verifying that 𝑥 equals five is a solution to the equation. In the same way, we can verify that 𝑥 equals negative 13 is a solution to the equation. Hence, if 𝑥 is a solution to the equation, then either 𝑥 equals five or 𝑥 equals negative 13.

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