Question Video: Determining the Time Taken for Charge to Flow in an Electric Device | Nagwa Question Video: Determining the Time Taken for Charge to Flow in an Electric Device | Nagwa

Question Video: Determining the Time Taken for Charge to Flow in an Electric Device Physics • Third Year of Secondary School

If an electric device that works at a 0.05 A electric current draws 4.25 C of charge, then the time taken by the charge to flow is _ s.

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Video Transcript

If an electric device that works at a 0.05-ampere electric current draws 4.25 coulombs of charge, then the time taken by the charge to flow is blank seconds. (A) 85, (B) 170, (C) 4.5, (D) 90.

In this problem, we are told that a particular electric device works at an electric current of 0.05 amperes and draws 4.25 coulombs of charge during some interval of time. We are asked to figure out what this time interval is, that is, how long it would take this device to draw the given amount of charge at the given current. Let’s begin by reminding ourselves of the equation that defines electric current.

The electric current through a point is equal to the total charge that flows through that point in a given amount of time divided by the length of time that it took for that charge to flow. We can write this using symbols as current 𝐼 is equal to charge 𝑄 divided by time 𝑡. Because the question is asking us to find the time it takes for the charge to flow, we need to rearrange this equation to make time 𝑡 the subject.

We can do this by first multiplying both sides by 𝑡. Canceling the 𝑡’s on the right-hand side, we have that 𝑡 times 𝐼 is equal to 𝑄. Then, we can divide both sides by 𝐼. Canceling the 𝐼’s on the left, we have that time 𝑡 is equal to charge 𝑄 divided by current 𝐼. We can now substitute in our values for the charge drawn 𝑄 and the current 𝐼. We have that 𝑄 equals 4.25 coulombs, and 𝐼 equals 0.05 amperes. Substituting these values, we have that 𝑡 is equal to 4.25 coulombs divided by 0.05 amperes.

Before evaluating this expression, let’s take a look at the units that we have. On the right-hand side, we have units of coulombs divided by units of amperes. Remember, though, that amperes are equivalent to coulombs per second. If we replace the units of amperes by coulombs per second in this expression, we can see that the coulombs then cancel from the numerator and denominator on the right-hand side. We’re then left with units of one over one over seconds, which is simply equal to units of seconds. This is good, because seconds are a valid unit of time. And we can notice from the question text that we’re expected to give our answer in these units of seconds.

Let’s now evaluate the expression. The time that it takes for this device to draw the charge is equal to 4.25 divided by 0.05, with units of seconds. This works out as 85 seconds. This means that it takes 85 seconds for this electric device to draw 4.25 coulombs of charge at an electric current of 0.05 amperes. This number of seconds is the value given in option (A). That means that option (A), 85, is the correct answer.

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