# Video: Solving Equations Involving an Inverse Trigonometric Function

Solve sinβ»ΒΉ π₯ + π = 3π/2.

01:33

### Video Transcript

Solve sin inverse of π₯ plus π equals three π over two.

To solve, we need to isolate this π₯-value. The first thing we would do is subtract π from both sides of the equation. On the left, π minus π cancels out. And weβre left with the sin inverse of π₯. On the right, we have three π over two minus π. We can rewrite π as two π over two.

And then we have something that says three π over two minus two π over two. Three π minus two π equals π. And we keep the denominator of two. And so, the sin inverse of π₯ equals π over two. To get rid of the sin inverse, we need to take the sin of the sin inverse of π₯. And if we take the sin of the left side of the equation, weβll need to take the sin of the right side of the equation.

The sin of the sin inverse of π₯ equals π₯. And that means π₯ equals the sin of π over two. We know that the sin of π over two equals one. Our π₯ must equal one.