### Video Transcript

Determine the indefinite integral
of negative sec squared six π₯ evaluated with respect to π₯.

To answer this question, itβs
almost simply enough to quote the general result for the integral of sec squared of
ππ₯. Itβs one over π times the tan of
ππ₯. It is sensible, though, to take a
factor of negative one outside of the integral as shown. And when we do, we obtain the
solution to be negative one times a sixth of tan six π₯ plus π. And all thatβs left is to
distribute the parentheses. Negative one times a sixth of tan
six π₯ is negative one-sixth tan of six π₯. And negative one times π gives us
this new constant, capital πΆ. And so we find our indefinite
integral to be negative one sixth of tan of six π₯ plus πΆ.