How much work does a supermarket checkout attendant do on a can of soup he pushes 0.600 meters horizontally with a force of 5.00 newtons?
In this scenario, we’re told the distance the can of soup is pushed, 0.600 meters, which we’ll call 𝑑. And we’re also told the force applied of 5.00 newtons, which we’ll call 𝐹. We want to know the work performed on the can of soup, which we’ll call capital 𝑊.
To determine the work done, let’s recall the definition for work. The work done on an object is equal to the force exerted on it multiplied by the distance it moves as a result of that force. In our case, the force 𝐹 is the force on the can of soup of 5.00 newtons, and the distance 𝑑 is the distance the can of soup is pushed, 0.600 meters.
Plugging these values in, when we multiply them together, we find the work done on the can of soup to be 3.00 joules. That’s how much work was done on the can over this distance.