### Video Transcript

In this video, weโll learn how to
calculate the sum of an infinite geometric sequence. Letโs begin by recalling what we
know about geometric sequences.

A geometric sequence is one which
has a common ratio between consecutive terms. In these cases, to get from one
term to the next, we multiply by that common ratio. And we can find the value of our
common ratio by therefore dividing any term by the term that precedes it. Now, for a geometric sequence with
a first term of ๐ and a common ratio ๐, the ๐th term is given by ๐ข sub ๐ equals
๐ times ๐ to the power of ๐ minus one. But we might also recall that we
can find the sum of a finite geometric sequence. And when we sum the terms in a
sequence, we call that a series.

For a geometric series with first
term ๐ and common ratio ๐, the sum of the first ๐ terms is ๐ times one minus ๐
to the ๐th power over one minus ๐. Itโs also worth remembering that
this is equivalent to ๐ times ๐ to the ๐th power minus one over ๐ minus one. Now, it isnโt necessary to switch
between these two forms, but it can be useful if we need to perform calculations by
hand. When ๐ is greater than one, we
tend to use this form. And if ๐ โ the common ratio โ is
less than one, we tend to use this form.

Now, the formulae weโve given so
far are really useful for solving problems involving geometric series. But what weโre interested in is
looking at how we might use these last formulae to find the sum of all of the terms
in a geometric series. Now, at this stage, you might be
thinking thatโs not possible. Surely, a series will contain
infinite terms, and so weโd expect the sum to be an infinitely large number. And to an extent, this is true. For example, take the sequence two,
four, eight, 16, and 32. The common ratio here is two. And so, as we progress through this
sequence, the terms get larger and larger. It follows then that the sum of all
of our terms would not be a number that we could evaluate.

But what about this sequence 32,
16, eight, four, two, and so on? This time, the common ratio is
one-half. And so, each time the terms halve
in size. This means our terms will get
smaller and smaller in size. In fact, as the number of terms in
our geometric series approaches โ, the terms themselves will approach zero. And this means that the sum of
these terms will actually approach a finite value. But whatโs the difference here? Why canโt we evaluate the sum of
all terms in our second sequence, but not the first? Well, itโs because the terms get
smaller and smaller, and this only happens when the common ratio is a number less
than one.

In fact, weโll generalize a little
bit further, and we say that if the absolute value of the common ratio is less than
one, then the geometric series is convergent, in other words, if ๐ is greater than
negative one and less than one. And if the series is convergent,
weโre able to then find the sum to โ. So, how can we use this fact to
find the sum of all of our terms? Letโs go back to one of our ๐ sub
๐ formulae and think about what happens as ๐ approaches โ. Well, since the modulus of ๐ is
less than one โ in other words, itโs a number between negative one and one โ as ๐
gets larger, ๐ to the power of ๐ will get smaller. As ๐ approaches โ, ๐ to the power
of ๐ approaches zero. And so, this means the sum to ๐
must approach ๐ times one minus zero over one minus ๐, which is simply ๐ over one
minus ๐.

Letโs formalize this. And we can say that for a
convergent geometric series, the sum to โ is equal to ๐ over one minus ๐. Itโs really, really important to
realize that if the series isnโt convergent โ in other words, if the modulus of the
common ratio is not less than one โ weโre not able to find the sum of an infinite
number of terms. Now that we have a definition,
weโre going to look at a few examples. In our first, weโll decide which
sequences can be summed to โ.

Which of the following geometric
sequences can be summed up to โ?

And then, weโre given five
sequences to choose from. We begin by recalling that a
geometric sequence is one which has a common ratio between terms. The ๐th term of a geometric
sequence is ๐๐ to the power of ๐ minus one, where ๐ is the first term and ๐ is
the common ratio. Now, we can sum a geometric
sequence to โ if itโs convergent. And this occurs when the modulus of
๐ or the absolute value of ๐, where ๐ is the common ratio, is less than one.

Now, weโre told that all of these
sequences are geometric sequences, and so our job is to find the common ratio. Letโs begin with sequence (A). Thatโs eight times six to the power
of ๐ minus five. Weโre going to need to write this
in this form: ๐ times ๐ to the power of ๐ minus one. And we can use one of our rules for
exponents to do so. We know that when we multiply two
exponential terms which have the same base, we simply add their exponents. And so, we can reverse this and say
that โWell, six to the power of ๐ minus five is the same as six to the power of
negative four times six to the power of ๐ minus one.โ Six to the power of negative four,
though, is one over six to the power of four. And so, we can rewrite this as
eight over six to the power of four times six to the power of ๐ minus one.

If we compare this to the general
๐th term of a geometric sequence, we see that ๐, which is the first term in this
sequence, is eight over six to the fourth power. ๐, however, is six. Now, itโs quite clear to us that
six is not less than one. We can, therefore, say that
sequence (A) is not convergent, and so we cannot sum it up to โ.

And so, we move on to sequence
(B). This time, we recall that we can
find the common ratio by dividing any term by the term that precedes it. And so, in this case, we can divide
three twenty-eighths by one twenty-eighth. And since the denominators of these
fractions is the same, thatโs three divided by one, which is three. Once again, three is not less than
one. And so, sequence (B) is not
convergent and cannot be summed to โ.

Letโs have a look at sequence (C)
now. Once again, weโll find the common
ratio by dividing the second term by the first. Remember, we would get the same
answer if we divided the third term by the second and so on. One method we have for dividing
fractions is to create a common denominator. Now, if we multiplied 263 by five,
we get 1315. So, 263 is equivalent to one
thousand three hundred and fifteen fifths. And so, we then divide the
numerators. And we find ๐ is equal to negative
789 over 1315. This value for ๐ is between
negative one and one. And so, we can say that the
absolute value of the common ratio in this sequence is less than one. This means itโs convergent and it
can be summed to โ.

Letโs just double-check the other
two sequences. By dividing the second term by the
first in sequence (D), we can see that the absolute value of the common ratio is not
less than one, and so it canโt be (D). And in fact, we get the same value
for the common ratio in sequence (E). And so that confirms to us that the
only geometric sequence in this list that can be summed to โ is (C).

In our next example, weโll find the
sum of a geometric series.

Find the sum of the geometric
series 13 over two plus 13 over four plus 13 over eight, and so on.

Weโre not told the number of terms
to find the sum of on this geometric series. And so, we need to assume that
weโre going to find the sum of all of the terms. In other words, we need to find the
sum to โ of this series. So, we recall that for a geometric
series with first term ๐ and common ratio ๐, the sum to โ is ๐ over one minus
๐. But this formula can only be
applied if the absolute value of the common ratio is less than one. And so, the first thing that weโre
going to do is just double-check that this geometric series is convergent, that the
absolute value of ๐ is less than one.

Now, we know that, for a geometric
sequence, we can find the value of the common ratio by dividing any term by the term
that precedes it. Letโs divide the second term by the
first. So, the common ratio is 13 over
four divided by 13 over two. And one technique that we have to
divide fractions is to make the denominators of those fractions the same. If we multiply the numerator and
denominator of 13 over two by two, we get 26 over four. And then, once the denominators are
the same, we simply divide the numerators. So, the common ratio is 13 over 26,
which is equal to one-half. Now, the absolute value of one-half
is just one-half, and that is indeed less than one. This means our geometric series is
indeed convergent, and weโre able to find the sum to โ.

๐, the first term in our series,
is clearly 13 over two. And we just calculated ๐ to be
equal to one-half. This means the sum to โ of our
series is 13 over two divided by one minus one-half. Now, one minus one-half is
one-half. So, weโre working out 13 over two
divided by one-half. And since the denominators are the
same, we simply divide the numerators. That tells us that the sum to โ is
13 divided by one, but thatโs 13. Now, since the sum to โ is the sum
of all terms of our geometric series, weโre finished. The sum of the geometric series
given is 13.

Weโll now consider how to find the
sum of an infinite geometric sequence given two of its terms.

Find the sum of an infinite
geometric sequence given the first term is 171 and the fourth term is 171 over
64.

We know that we can find the sum of
a convergent geometric sequence by using the formula sum to โ is ๐ over one minus
๐. And the sequence is said to be
convergent if the absolute value of its ratio is less than one. Now, ๐ is the first term in the
sequence, and weโre told that the first term is 171. But what is the common ratio? Well, weโll use the general formula
for the ๐th term in a geometric sequence to find this.

This is ๐ times ๐ to the power of
๐ minus one, where once again ๐ is the first term and ๐ is the common ratio. Weโll combine this with the fact
that the fourth term in the sequence is 171 over 64. And this means that ๐ข sub four is
171, thatโs ๐, times ๐ to the power of four minus one or ๐ cubed. But in fact, we know the value of
๐ข sub four. Itโs 171 over 64. And so, our equation is 171 over 64
equals 171 times ๐ cubed. Letโs divide both sides of this
equation by 171. And so, ๐ cubed is equal to one
over 64.

We can solve for ๐ by taking the
cube root of both sides, and we find that ๐ is the cube root of one over 64, which
is simply equal to one-quarter. The absolute value of one-quarter
is just one-quarter; itโs less than one. And so, weโve confirmed that the
geometric sequence is indeed convergent. And we now know the value of ๐,
thatโs 171, and ๐.

Letโs substitute everything we know
into the formula. We get 171 over one minus
one-quarter as being the sum to โ, in other words, the sum of all terms in our
sequence. Thatโs 171 over three-quarters. Now, of course, we can divide by a
fraction by multiplying by the reciprocal of that fraction. Thatโs the same as 171 times four
over three. Then, we cross-cancel by dividing
171 and three by three, meaning weโre left with 57 times four over one, which is
just 57 times four. And thatโs equal to 228. And we can, therefore, say that the
sum of an infinite geometric sequence with a first term of 171 and a fourth term of
171 over 64 is 228.

In our final example, weโll look at
how we can use this very same process to convert a recurring decimal to a
fraction.

Express 0.375 recurring as a common
fraction.

Now, at first glance, it might seem
like this hasnโt got anything to do with finding the sum of a geometric series. However, letโs look at the decimal
0.375 recurring and find an alternative way to write it. We know that each of the digits
three seven five recur. So, itโs 0.375375375 and so on. And then, we can split this decimal
up, and we can say that itโs the sum of 0.375, 0.000375, and 0.000000375. It might even help to write each of
those as a fraction, so 375 over 1000, 375 over a million, and so on.

We do indeed now have a geometric
series. The common ratio in this series is
one one thousandth. Now, we could convince ourselves
that is true by dividing any term by the term that precedes it. And since the absolute value of one
one thousandth is just one one thousandth and that is less than one, we can say that
the geometric series weโve created is convergent. And since itโs convergent, weโre
able to calculate the sum to โ. In other words, weโre able to sum
all of its terms. The formula we use is ๐ over one
minus ๐, where ๐ is the first term and ๐ is the common ratio.

Now, we see that the first term in
our series is 375 over 1000, and ๐ is one over 1000. And so, our sum to โ must be 375
over 1000 divided by one minus one over 1000. The denominator of this fraction
just simplifies to 999 over 1000. And we see that weโre dividing a
pair of fractions whose denominator is equal. In this case then, we can simply
calculate the quotient by dividing their numerators. Thatโs 375 over 999. Wherever possible, we should
simplify our fraction. And we can indeed divide both the
numerator and the denominator of our quotient by three. When we do, we find that 375
divided by three is 125 and 999 divided by three is 333. The sum of our geometric series
then, which we said was equal to 0.375 recurring, is 125 over 333. And so, weโve written our recurring
decimal as a common fraction.

Letโs recap the key points from
this lesson. In this lesson, we learned that if
the absolute value of the common ratio ๐ of a geometric sequence is less than one,
then we say that that sequence is convergent. We saw that when we find the sum of
all of the terms in a geometric sequence, we call that a series. And if this is the case, if the
absolute value of ๐ is less than one for this series, we can evaluate its sum. In other words, we can find the sum
of all of its terms. We call this the sum to โ of the
series. And itโs calculated by dividing ~~๐~~, ๐
thatโs the first term, by one minus ๐, where ๐, of course, is the common
ratio. Finally, we saw that by writing a
recurring decimal as a geometric series, we can actually use this process to convert
it into a fraction.