Video: AQA GCSE Mathematics Higher Tier Pack 1 β€’ Paper 2 β€’ Question 4

AQA GCSE Mathematics Higher Tier Pack 1 β€’ Paper 2 β€’ Question 4

01:18

Video Transcript

A straight line has the equation 𝑦 minus three π‘₯ minus five equals zero. Circle the 𝑦-intercept of the line: five, negative five, three, or negative three.

So we are given that we’re working with a straight line. And a straight line will have the equation form of 𝑦 equals π‘šπ‘₯ plus 𝑐, where π‘š is the gradient of the line, the slope of the line, and 𝑐 is the 𝑦-intercept of the line, where this line, if it were graphed, it would cross the 𝑦-axis here.

So here’s our equation. We need to put it in the right form. So we need to move the negative three π‘₯ and the negative five, because we need 𝑦 to be isolated, all by itself. So we need to add three π‘₯ to both sides of the equation and add five to both sides of the equation. This way, we only have 𝑦 on the left-hand side.

Now we have zero plus three π‘₯ plus five. So three π‘₯ is just three π‘₯. And then zero and five we can combine to be five. So if 𝑦 equals three π‘₯ plus five is the equation of our straight line, the 𝑦-intercept would be found here at the end of the equation. It’s the constant number, so five. Therefore, the number that we have circled is five.

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