# Video: AQA GCSE Mathematics Higher Tier Pack 1 β’ Paper 2 β’ Question 4

AQA GCSE Mathematics Higher Tier Pack 1 β’ Paper 2 β’ Question 4

01:18

### Video Transcript

A straight line has the equation π¦ minus three π₯ minus five equals zero. Circle the π¦-intercept of the line: five, negative five, three, or negative three.

So we are given that weβre working with a straight line. And a straight line will have the equation form of π¦ equals ππ₯ plus π, where π is the gradient of the line, the slope of the line, and π is the π¦-intercept of the line, where this line, if it were graphed, it would cross the π¦-axis here.

So hereβs our equation. We need to put it in the right form. So we need to move the negative three π₯ and the negative five, because we need π¦ to be isolated, all by itself. So we need to add three π₯ to both sides of the equation and add five to both sides of the equation. This way, we only have π¦ on the left-hand side.

Now we have zero plus three π₯ plus five. So three π₯ is just three π₯. And then zero and five we can combine to be five. So if π¦ equals three π₯ plus five is the equation of our straight line, the π¦-intercept would be found here at the end of the equation. Itβs the constant number, so five. Therefore, the number that we have circled is five.