# Video: AQA GCSE Mathematics Higher Tier Pack 1 • Paper 2 • Question 4

AQA GCSE Mathematics Higher Tier Pack 1 • Paper 2 • Question 4

01:18

### Video Transcript

A straight line has the equation 𝑦 minus three 𝑥 minus five equals zero. Circle the 𝑦-intercept of the line: five, negative five, three, or negative three.

So we are given that we’re working with a straight line. And a straight line will have the equation form of 𝑦 equals 𝑚𝑥 plus 𝑐, where 𝑚 is the gradient of the line, the slope of the line, and 𝑐 is the 𝑦-intercept of the line, where this line, if it were graphed, it would cross the 𝑦-axis here.

So here’s our equation. We need to put it in the right form. So we need to move the negative three 𝑥 and the negative five, because we need 𝑦 to be isolated, all by itself. So we need to add three 𝑥 to both sides of the equation and add five to both sides of the equation. This way, we only have 𝑦 on the left-hand side.

Now we have zero plus three 𝑥 plus five. So three 𝑥 is just three 𝑥. And then zero and five we can combine to be five. So if 𝑦 equals three 𝑥 plus five is the equation of our straight line, the 𝑦-intercept would be found here at the end of the equation. It’s the constant number, so five. Therefore, the number that we have circled is five.