Question Video: Studying the Collision of Two Moving Bodies in the Same Line in Two Different Cases | Nagwa Question Video: Studying the Collision of Two Moving Bodies in the Same Line in Two Different Cases | Nagwa

Question Video: Studying the Collision of Two Moving Bodies in the Same Line in Two Different Cases Mathematics • Third Year of Secondary School

Two spheres are moving along a straight line. One has a mass of 𝑚 and is moving at speed 𝑣, whereas the other one has a mass of 10 g and is moving at 36 cm/s. If the two spheres were moving in the same direction when they collided, they would coalesce into one body and move at 30 cm/s in the same direction. However, if they were moving in opposite directions, they would coalesce into one body, which would move at 6 cm/s in the direction the first sphere had been traveling. Find 𝑚 and 𝑣.

03:18

Video Transcript

Two spheres are moving along a straight line. One has a mass of 𝑚 and is moving at speed 𝑣, whereas the other one has a mass of 10 g and is moving at 36 centimeters per second. If the two spheres were moving in the same direction when they collided, they would coalesce into one body and move at 30 centimeters per second in the same direction. However, if they were moving in opposite directions, they would coalesce into one body, which would move at six centimeters per second in the direction the first sphere had been traveling. Find 𝑚 and 𝑣.

With the information we’ve been given, we’re going to set up a pair of simultaneous equations in 𝑚 and 𝑣 using conservation of momentum. In particular, we’re going to use the formula momentum is equal to mass times velocity.

Let’s begin by identifying the direction to the right to be positive. Then, we can say the momentum of the first sphere is 𝑚 times 𝑣. The momentum of the second sphere is 10 times 36. That’s 360, giving us a total or net momentum before the collision of 𝑚𝑣 plus 360. By the conservation of momentum, we know this must be equal to the net momentum after the collision. The new mass of the body is 10 plus 𝑚, whilst its velocity is 30. Since it’s in the same direction, it’s still positive, meaning the momentum after the collision is 30 times 10 plus 𝑚. By distributing parentheses and rearranging, we can form an equation, 60 equals 30𝑚 minus 𝑚𝑣.

Now that we have this equation, let’s complete the process for the second scenario. In this scenario, these spheres are moving in opposite directions. This means the velocity of the second sphere must be negative 36. So the net momentum is 𝑚𝑣 minus 360 before the collision. After the collision, they coalesce, giving us a total mass of 10 plus 𝑚. And they move at six centimeters per second, still in the positive direction. This time, if we distribute the parentheses and rearrange, we get the equation negative 420 equals six 𝑚 minus 𝑚𝑣.

And now we might observe that we can quite quickly calculate the value of 𝑚 here. We have a system of equations in which we have the same term negative 𝑚𝑣. Let’s define these equations to be one and two, respectively. Then, if we subtract one equation from the other, and it doesn’t matter which way round we do it, that negative 𝑚𝑣 term will disappear. 60 minus negative 420 is 480. Then, 30𝑚 minus six 𝑚 is 24𝑚, and negative 𝑚𝑣 minus negative 𝑚𝑣 is zero. If we then divide through by 24, we find that 𝑚 is equal to 20 or 20 grams.

Then, we can find the value of 𝑣 by substituting it into either of our earlier equations. When we do, we get 60 equals 30 times 20 minus 20𝑣, which gives us negative 540 equals negative 20𝑣. Finally, we divide through by negative 20, and we find 𝑣 is equal to 27 centimeters per second. 𝑚 is 20 grams and 𝑣 is 27 centimeters per second.

Join Nagwa Classes

Attend live sessions on Nagwa Classes to boost your learning with guidance and advice from an expert teacher!

  • Interactive Sessions
  • Chat & Messaging
  • Realistic Exam Questions

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy