### Video Transcript

Let π₯ be equal to the fifth root
of the cubed root of seven over the fourth root of two. Which of the following numbers is
rational? (A) π₯ cubed, (B) π₯ to the fourth
power, (C) π₯ to the 12th power, (D) π₯ to the 15th power, or (E) π₯ to the 60th
power.

Before we start, there are two
things we should think about, the first of them being what is a rational number. A rational number is a number that
can be written in the form π over π, where π and π are integers and π is not
equal to zero. Another way to say this is that a
rational number can be made by dividing two integers.

Now, the second thing we might want
to think about is seeing if we can simplify what π₯ is equal to here. To do that, letβs think about our
exponent rule that tells us that the πth root of π₯ is equal to π₯ to the one over
π power. And that means we can rewrite the
fifth root as the one-fifth power. And we wanna repeat this process
with the two roots inside the parentheses, which means weβll have seven to the
one-third power over two to the one-fourth power, all taken to the one-fifth
power.

And one further step we can do to
simplify is remember the power of a power rule that tells us π₯ to the π power to
the π power is equal to π₯ to the π times π power. And this means we can multiply
one-third by one-fifth. When we do that, we multiply the
numerators, one times one is one, then multiply the denominators, three times five
is 15. Weβll have seven to the 15th
power.

And then weβll need to multiply
one-fourth times one-fifth to find the power of our denominator. One-fourth times one-fifth is one
twentieth. And so weβre saying that π₯ is
equal to seven to the one fifteenth power over two to the one twentieth power. To find a rational value, we need
the numerator and the denominator here to be an integer. So letβs consider some of our
options.

If we cube π₯, weβll have seven to
the one fifteenth power over two to the one twentieth power cubed. And if we were going to take a
power of a power, we would multiply these powers together. We would have π₯ cubed being equal
to seven to the three fifteenth power over two to the three twentieths power.

Now, we could plug this value into
our calculator to see what would happen. When we do that, we get 1.3304
continuing. This is an irrational value. And so maybe we should consider
what kind of powers here would give us integers. If our exponents were whole
numbers, if we were taking seven to an integer power, the outcome would be an
integer. And that means we want to take both
two and seven to some power of an integer. We need to multiply one fifteenth
and one twentieth by some number that produces an integer for both of these
values.

For example, if we took π₯ to the
15th power, then we would have seven to the first power. But we would still have a fraction
in our denominator. But that does get us a bit
closer. From our list, we can take π₯ to
the 60th power, which would be seven to the 60 over 15 power and two to the 60 over
20 power. 60 divided by 15 is four. 60 divided by 20 is three. π₯ to the fourth power will be an
integer, and two cubed will also be an integer. An integer divided by an integer is
a rational number. And so we can say that π₯ to the
60th power will be rational.