### Video Transcript

Is the function π of π₯ equals π₯
to the fifth power times tan of six π₯ to the fourth power even, odd, or neither
even nor odd?

Letβs recall how we check the
parity of a function. The first thing we do is check the
domain of the function. We need that to be centered at π₯
equals zero. Then, if the answer is no, we can
say that the function is neither even nor odd without performing any further
tests. If the answer is yes, though, we
say that it will be even if it satisfies π of negative π₯ equals π of π₯. And it will be odd if it satisfies
π of negative π₯ equals negative π of π₯. Then, of course, if it satisfies
neither of these, it will be neither even nor odd.

So letβs think about the domain of
our function. Our function is the product of two
functions. Itβs the product of π₯ to the fifth
power and tan of six π₯ to the fourth power. And so the domain of π of π₯ will
be the intersection of the domains of the respective parts of the function. Well, π₯ to the fifth power is a
polynomial, so its domain is the set of real numbers or the open interval from
negative β to β. But what about the domain of the
trigonometric part? Well, itβs all real numbers, except
those that make cos of six π₯ equal to zero. But since the values of π₯ that
make cos of six π₯ equal to zero are symmetrical about the π¦-axis, then we can say
that the domain of tan of six π₯ to the fourth power must be centered at π₯ equals
zero.

Since both domains are centered at
π₯ equals zero, then we can answer yes to this first question, and weβre able to
move on. We now see that itβs even if π of
negative π₯ is equal to π of π₯ and odd if itβs equal to negative π of π₯. And so letβs evaluate π of
negative π₯. To do so, we replace each instance
of π₯ in our original function with negative π₯. And we get π of negative π₯ is
negative π₯ to the fifth power times tan of negative six π₯ to the fourth power. Weβll evaluate each part in
turn. Letβs begin with negative π₯ to the
fifth power. Since the exponent is odd, when we
multiply this out, weβre going to get a negative result. Negative π₯ to the fifth power is
as shown.

But what about the tan
function? Well, we can actually quote the
result that tan of π₯ is odd, meaning that tan of negative π₯ is equal to negative
tan of π₯ and, in turn, the tan of negative six π₯ is equal to negative tan of six
π₯. But of course, weβre raising this
to the fourth power. Weβre raising it to an even
exponent. And we know when we raise a
negative number to an even exponent, the result is positive. And so tan of negative six π₯ to
the fourth power is just tan of six π₯ to the fourth power.

And so π of negative π₯ is
therefore equal to negative π₯ to the fifth power times tan of six π₯ to the fourth
power. So does this satisfy either of our
criteria, is it even or odd? Well, yes. If we look at it carefully, we see
itβs the same as negative π of π₯. π of negative π₯ is equal to
negative π of π₯. And so the function must be
odd.