Question Video: Determining the Change in Potential Difference after Adding a Resistor in Parallel | Nagwa Question Video: Determining the Change in Potential Difference after Adding a Resistor in Parallel | Nagwa

Question Video: Determining the Change in Potential Difference after Adding a Resistor in Parallel Physics • Third Year of Secondary School

In the circuit, what will happen to the potential difference across the lamp filament when connecting a resistor in parallel with it?

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Video Transcript

In the circuit below, what will happen to the potential difference across the lamp filament when connecting a resistor in parallel with it? (A) It will stay the same. (B) It cannot be determined without knowing the resistance values of the lamp and the resistor. (C) It will increase. (D) It will decrease.

In this question, we’re shown this diagram. Currently, the circuit diagram consists of a cell and a lamp filament. If the cell provides a potential difference of 𝑉, then the potential difference across the lamp filament will also be 𝑉. Now we will add a resistor in parallel with the lamp filament to see how the potential difference across the lamp filament changes. So we now have a parallel circuit. The path between the two terminals of the cell splits into two paths at point 𝐴. The paths then join together again at point 𝐵. The cell will still provide a potential difference of 𝑉 to the circuit, as the cell did not change in emf.

Let’s recall that the potential difference across each path of a parallel circuit is the same. No matter what the resistance values of the components along the parallel paths are, the potential difference across each will be the same. And in this case, that potential difference will be equal to 𝑉, the potential difference of the cell. That is, the potential difference across the resistor is 𝑉, and the potential difference across the lamp filament is also equal to 𝑉, the same as it was before adding the resistor in parallel.

Therefore, when adding a resistor in parallel with a lamp filament, the potential difference across the lamp filament will remain the same. So, option (A) is the correct answer; it will stay the same.

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